Scala中两个时间戳之间的秒数差 [英] Difference in seconds between two timestamps in Scala
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问题描述
所以我有一个以下格式的时间戳:
1990-10-31 18:43:12
我要计算其中两个时间戳之间的差值。
我尝试的内容:
val t1 = new java.text.SimpleDateFormat("yyyy-mm-dd HH:mm:ss")
val t2 = new java.text.SimpleDateFormat("yyyy-mm-dd HH:mm:ss")
t1.parse(timestamp1)
t2.parse(timestamp2)
但之后我该怎么办?
推荐答案
首先,JAVA现在有java.time
(JDK1.8及更高版本)
import java.time._
import java.time.format._
然后(请注意,格式化程序/解析器现在是无状态的,重用它们总是安全的):
val p = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss") //note months are MM
val t1 = LocalDateTime.parse(timestamp1, p)
val t2 = LocalDateTime.parse(timestamp2, p)
现在您有两个日期/时间,您需要转换为Instant(实际上是ZonedDateTime
,但已经足够了):
val i1 = t1.atZone(ZoneId.of("Europe/London"))
val i2 = t2.atZone(ZoneId.of("Europe/London"))
现在您有两个时刻,您可以将它们区分开来:
import java.time.temporal._
val diff = i1.until(i2, ChronoUnit.SECONDS) //Or MILLIS, MICROS etc
附录
以下是REPL会议:
scala> :paste
// Entering paste mode (ctrl-D to finish)
val timestamp1 = "1990-10-31 18:43:12"
val timestamp2 = "1991-09-29 18:43:12"
import java.time._
import java.time.format._
val p = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss")
val t1 = LocalDateTime.parse(timestamp1, p)
val t2 = LocalDateTime.parse(timestamp2, p)
val i1 = t1.atZone(ZoneId.of("Europe/London"))
val i2 = t2.atZone(ZoneId.of("Europe/London"))
import java.time.temporal._
val diff = i1.until(i2, ChronoUnit.SECONDS)
结果如下:
// Exiting paste mode, now interpreting.
timestamp1: String = 1990-10-31 18:43:12
timestamp2: String = 1991-09-29 18:43:12
import java.time._
import java.time.format._
p: java.time.format.DateTimeFormatter = Value(YearOfEra,4,19,EXCEEDS_PAD)'-'Value(MonthOfYear,2)'-'Value(DayOfMonth,2)' 'Value(HourOfDay,2)':'Value(MinuteOfHour,2)':'Value(SecondOfMinute,2)
t1: java.time.LocalDateTime = 1990-10-31T18:43:12
t2: java.time.LocalDateTime = 1991-09-29T18:43:12
i1: java.time.ZonedDateTime = 1990-10-31T18:43:12Z[Europe/London]
i2: java.time.ZonedDateTime = 1991-09-29T18:43:12+01:00[Europe/London]
import java.time.temporal._
diff: Long = 28767600
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