如何发送模型_Layout.cshtml（我需要再派模型索引视图太） [英] How to send Model to _Layout.cshtml (I need to send another model to Index view too)

问题描述

我需要发送2个不同的模式，一个索引视图，另一种为 _Layout.cshtml ，我该怎么办呢？

I need to send 2 different Models, one to Index view and another one to _Layout.cshtml, how I can do it?

我的的HomeController ：

[Route("")]
public ActionResult Index()
{
    HomeViewModel model = new HomeViewModel();
    model.A = _repoA.GetLatest(4);
    model.B = _repoB.GetLatest(4);
    model.C = _repoC.GetLatest(4);
    return View(model);
}

我不喜欢使用 ViewBag ，的ViewData ＆安培; ......，我在寻找传递模型相同的方式，我们通过模型查看。

I don't like using ViewBag, ViewData & ..., I'm looking for passing the model in same way as we passing model to Views.

推荐答案

您可以将这个在布局加载每次的部分... pretty加载有用的一块动态菜单或构件的每一页上。

You can place this in your Layout to load a partial each time... Pretty useful for loading in a piece of a dynamic menu or a widget on each page.

随着这条线在你的布局你可以做你的索引页，你通常会。

Along with this line in your layout you can just do your Index page as you normally would.

@{ Html.RenderAction("_widget", "Home"); }

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