XML发布到传统的ASP页面和检索页面上的数据后 [英] Post XML to classic asp page and retrieve the post data on page
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问题描述
要后下code传统的ASP页面上的数据我使用
暗淡stringXML,HTT prequest,postResponsestringXML =< XML版本=1.0,编码=UTF-8><学校><类> 5℃/类>< /学校>中设置HTT prequest =的Server.CreateObject(MSXML2.ServerXMLHTTP.6.0)
HTT prequest.OpenPOST,HTTP://www.mywebpage/TestVBScript/RecieveRequest.asp,真
HTT prequest.SetRequestHeader内容类型,文本/ XML
HTT prequest.Send stringXML
现在我想要得到RecieveRequest.asp页面上的stringXML值。这样我可以处理我的XML,并发送回响应
任何帮助将AP preciated。在此先感谢
解决方案
暗淡stringXML,HTT prequest,postResponsestringXML =< XML版本=1.0,编码=UTF-8><学校><类> 5℃/类>< /学校>中设置HTT prequest =的Server.CreateObject(MSXML2.ServerXMLHTTP.6.0)
HTT prequest.OpenPOST,HTTP://www.mywebpage/TestVBScript/RecieveRequest.asp,真
HTT prequest.SetRequestHeader内容类型,文本/ XML
HTT prequest.setRequestHeader的Content-Length,LEN(stringXML)
HTT prequest.Send stringXML如果HTT prequest.status = 200然后
TextResponse = HTT prequest.responseText
XMLResponse = HTT prequest.responseXML
StreamResponse = HTT prequest.responseStream
其他
'在这里处理缺失反应或其他错误
万一设置HTT prequest =什么
To post data on classic asp page i am using below code
Dim stringXML, httpRequest, postResponse
stringXML = "<?xml version=""1.0"" encoding=""UTF-8""?><School><Class>5</Class></School>"
Set httpRequest = Server.CreateObject("MSXML2.ServerXMLHTTP.6.0")
httpRequest.Open "POST", "http://www.mywebpage/TestVBScript/RecieveRequest.asp", True
httpRequest.SetRequestHeader "Content-Type", "text/xml"
httpRequest.Send stringXML
Now I want to get the stringXML value on RecieveRequest.asp page. So that i can process my XML and send back the response
Any help will be appreciated. Thanks in advance
解决方案
Dim stringXML, httpRequest, postResponse
stringXML = "<?xml version=""1.0"" encoding=""UTF-8""?><School><Class>5</Class></School>"
Set httpRequest = Server.CreateObject("MSXML2.ServerXMLHTTP.6.0")
httpRequest.Open "POST", "http://www.mywebpage/TestVBScript/RecieveRequest.asp", True
httpRequest.SetRequestHeader "Content-Type", "text/xml"
httpRequest.setRequestHeader "Content-Length", Len(stringXML)
httpRequest.Send stringXML
If httpRequest.status = 200 Then
TextResponse = httpRequest.responseText
XMLResponse = httpRequest.responseXML
StreamResponse = httpRequest.responseStream
Else
' Handle missing response or other errors here
End If
Set httpRequest = Nothing
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