拆分实体集合为n个部分 [英] Split a entity collection into n parts

问题描述

我有一个数据库表。

• 首先，我想按日期和时间。
• 然后我想只能选择组，n项。

我的阶级是这样的：

public class VisitDate
{
  public int Id {get;set;}
  public int VisitMeDate {get;set;}
  .....
  .....
}

我的SQL表就像如下：

My SQL table is like below:

Id   Date
--- -----------------------
136 2012-05-09 10:00:00.000
167 2012-05-09 12:00:00.000
137 2012-05-10 10:00:00.000
168 2012-05-10 12:00:00.000
194 2012-05-10 14:00:00.000
138 2012-05-11 10:00:00.000
169 2012-05-11 12:00:00.000
195 2012-05-11 14:00:00.000
139 2012-05-12 10:00:00.000
170 2012-05-12 12:00:00.000
196 2012-05-12 14:00:00.000
140 2012-05-13 10:00:00.000
171 2012-05-13 12:00:00.000
197 2012-05-13 14:00:00.000
141 2012-05-14 10:00:00.000
142 2012-05-15 10:00:00.000
172 2012-05-15 12:00:00.000
143 2012-05-16 10:00:00.000
173 2012-05-16 12:00:00.000
144 2012-05-17 10:00:00.000
174 2012-05-17 12:00:00.000
198 2012-05-17 14:00:00.000

我要转换如下图所示：

I want to transform like below:

List<List<MyEntity>> = ?;

137 2012-05-10 10:00:00.000
168 2012-05-10 12:00:00.000
194 2012-05-10 14:00:00.000

138 2012-05-11 10:00:00.000
169 2012-05-11 12:00:00.000
195 2012-05-11 14:00:00.000

139 2012-05-12 10:00:00.000
170 2012-05-12 12:00:00.000
196 2012-05-12 14:00:00.000

140 2012-05-13 10:00:00.000
171 2012-05-13 12:00:00.000
197 2012-05-13 14:00:00.000

144 2012-05-17 10:00:00.000
174 2012-05-17 12:00:00.000
198 2012-05-17 14:00:00.000

我尝试这样做：

I tried this:

List<List<VisitDate>> dates = dbContext.VisitDates.GroupBy(f => new { f.VisitMeDate }).ToList();

不过，这并不编译，我不知道怎么说，我只想组，三个元素。

But it doesn't compile and I don't know how to say that I only want groups with three elements.

推荐答案

尝试是这样的：

var result = dbContext.VisitDates
                      .GroupBy(x => x.VisitMeDate.Date)
                      .Where(g => g.Count() == 3)
                      .Select(g => g.ToList())
                      .ToList();

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