如何切换到一个框架，并在弹出点击了使用网络驱动程序（硒 - Java的）？ [英] How do I switch to a Frame and click on the pop up using web driver (Selenium - Java)?
问题描述
<iframe height="0" frameborder="0" width="500" scrolling="no" style="position: absolute; top: 185.5px; left: 460.5px; height: 357px; width: 500px; z-index: 10002; border: medium none; background-color: rgb(255, 255, 255); opacity: 0;" src="/foresee/shim.gif" alt="Survey Invitation Helper Window - Please Ignore">
<html>
<head>
<meta name="viewport" content="width=device-width; height=device-height;">
<style>
<title>shim.gif (GIF Image, 1 × 1 pixels)</title>
</head>
<body>
<img src="https://www3-qan.tivo.com/foresee/shim.gif" alt="https://www3-qan.tivo.com/foresee/shim.gif">
</body>
</html>
</iframe>
<div class="fsrwin" style="position: absolute; width: 500px; z-index: 10005; left: 460.5px; top: 185.5px; opacity: 1;">
<div class="innerwin">
<div class="fsr_top">
<div class="fsr_middle">
<div class="fsr_closeBody fsr_closeButtons">
<button id="decline" class="fsr_closeSticky fsr_button fsr_decline">No thanks</button>
<button id="accept" class="fsr_closeSticky fsr_button fsr_accept">Yes, I'll give feedback</button>
</div>
我知道我应该切换到机架上，以做任何操作在框架中。
I understand that I should switch to frame in order to do to any operations in the frame.
我在那里的问题是：
-
如何切换到帧？ （我无法找出正确的
定位在switch语句中使用（driver.switchto（）。框架（什么
应该GO HERE）））？
How do I switch to frame? (I am not able to figure out the right locator to use in the switch statement (driver.switchto().frame("WHAT SHOULD GO IN HERE")))?
有没有一种方法来检查，如果当我浏览到一个新的存在，这架
网页每一次？
Is there a way to check if this frame exists when i navigate to a new page every time?
由于一吨的帮助....
迈克
Thanks a ton for the help.... Mike
推荐答案
如果该框架是页面上唯一的框架，那么你可以用
If the frame is the only frame on the page then you can go with
driver.switch.frame（0）; //不是一个很好的，虽然
driver.switch.frame(0); //not a good way though
或
您可以使用XPath或任何识别您的iframe，然后使用如下
you can use xpath or anything to identify your iframe and then use that as below
driver.switch.frame(driver.findElementByXpath("//iframe[contains(@src,'forsee')]"))
元素标识应上述unique..the的XPath仅仅是一个way..but它可能不是你的整个HTML unique..depends。
The element identification should be unique..the xpath given above is just one way..but it might not be unique..depends on your entire html.
希望有所帮助。
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