提取物对模式的任何一端由一个标识符封闭的多条线路 [英] Extract multiple lines on either end of pattern which are enclosed by an identifer

问题描述

我想从日志文件中提取特定事件的痕迹。为了找到相关的事件，我找了$模式$。要提取该事件​​的完整的曲线，我期待在由$ $ SEPARATOR包围的图案两端提取线

I am trying to extract the trace of a specific event from log files. To find the relevant event, I look for a $PATTERN$. To extract the complete trace of the event, I am looking to extract lines on either end of the pattern enclosed by a $SEPARATOR$

例如，如果日志文件的内容是

For example, if the contents of log file is

Line1
Line2
SEP
Line3
Line4
Name=PATTERN
Line5
SEP
Line 6
...

我要提取

SEP
Line3
Line4
Name=PATTERN
Line5
SEP

我试图用sed和免费得到它的单行工作如下一致：

I tried to use sed and got it working for single line matches as below:

echo "randomStringSEPrandomPATTERNrandomSEPrandom" | sed -n 's/^.*\(SEP.*PATTERN.*SEP\).*/\1/p'

收益 SEPrandomPATTERNrandomSEP

如何将其扩展为多行任何帮助将是非常美联社preciated。谢谢你。

Any help on how to extend it for multiple lines would be much appreciated. Thanks.

推荐答案

这是不是 SED 一个很自然的事。使用 AWK 代替。

This is not a very natural task for sed. Use awk instead.

A GAWK 特异性的版本（感谢Jotne更正）：

A gawk-specific version (thanks Jotne for corrections):

gawk -vRS="SEP" '/PATTERN/ {print RT $0 RT}'

一个对POSIX awk的版本。应在BSD / OSX工作。

A version for POSIX awk. Should work on BSD/OSX.

awk '
  /SEP/ {
    out = out $0 "\n"
    if (in_seps == 1) {
      if (pattern_found) {
        printf(out)
        pattern_found = 0
      }
      in_seps = 0
      out = ""
    } else
      in_seps = 1
    next
  }

  in_seps == 1 {
    out = out $0 "\n"
  }

  /PATTERN/ {
    pattern_found = 1
  }
'

A 的sed 脚本。使用GNU扩展T（如T，但相反的情况）。

A sed script. Uses GNU extension T (like t but opposite condition).

sed -n '
  H               # append line to holdspace
  /SEP/ {         # if line was a separator
    x             # exchange pattspace and holdspace
    s/^SEP/&/     # check if it begins with a separator
    T             # if it doesn't, go to next line
    s/PATTERN/&/  # check if it contains the pattern
    T             # if it doesn't, go to next line
    p             # print it
  }
'

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