更换一定数量的数字范围 [英] Replace range of numbers with certain number

问题描述

我需要一定数量的更换范围内的数字。我真的努力很难code将其与自己的sed（像sedS / [33-64] / 64 /）或AWK，但总是得到错误的结果。它往往以取代个位数，而不是数字...我需要将什么：更换0-32 - 它们之间> 255 - > 32，33-64 - > 64，65-128 - > 128，129-255数字IP地址，它应该保持不变。我觉得这个命令选择所有，但IP地址：

  sed的'/ [0-9] \\ {1,3 \\} \\。[0-9] \\ {1,3 \\} \\。[0-9] \\ { 1,3 \\} \\。[0-9] \\ {1,3 \\} /！ ......
 

所以我有一个这样的文件：

  65.74.16.161
232
10.128.8.72
63
10.128.14.13
100
10.128.8.58
32
10.128.4.129
60
10.128.240.18
59
 

和它应该是这样的：

  65.74.16.161
255
10.128.8.72
64
10.128.14.13
128
10.128.8.58
32
10.128.4.129
64
10.128.240.18
64
 

解决方案

的 [33-64] 定义字符类，是写作的一种有趣的方式 [3-6] 键，确实只匹配单个字符 - 如果你真的想与 SED ，而你关心从33到64的值，那么你必须把它不同的写出来 - 而且更冗长

在部分这取决于哪个版本的 SED 你有。将与经典的 SED 工作的解决方案是：

 的sed -e'S / ^ [0-9] $ / 32 /'\\
    -e的/ ^ [12] [0-9] $ / 32 /'\\
    -e'S / ^ 3 [012] $ / 32 /'\\
    -e'S / ^ 3 [3-9] $ / 64 /'\\
    -e的/ ^ [45] [0-9] $ / 64 /'\\
    -e'S / ^ 6 [0-4] $ / 64 /'\\
    -e'S / ^ 6 [5-9] $ / 128 /'\\
    -e的/ ^ [7-9] [0-9] $ / 128 /'\\
    -e'S / ^ 1 [01] [0-9] $ / 128 /'\\
    -e'S / ^ 12 [0-8] $ / 128 /'\\
    -e'S / ^ $ 129/255 /'\\
    -e'S / ^ 1 [3-9] [0-9] $ / 255 /'\\
    -e'S / ^ 2 [0-4] [0-9] $ / 255 /'\\
    -e'S / ^ 25 [0-5] $ / 255 /'
 

但是，正如你所看到的，这是很痛苦的。如果你有GNU SED ，您可以使用 -r 选项启用扩展的正前pressions;如果你有Mac OS X或BSD SED ，您可以使用 -E 选项启用扩展的正前pressions。然后你就可以减少上方来的code：

  SED-E \\
    -e'S / ^（[0-9] | [12] [0-9] | 3 [012]）$ / 32 /'\\
    -e'S / ^（3 [3-9] | [45] [0-9] | 6 [0-4]）$ / 64 /'\\
    -e'S / ^（6 [5-9] | [7-9] [0-9] | 1 [01] [0-9] | 12 [0-8]）$ / 128 /'\\
    -e'S / ^（129 | 1 [3-9] [0-9] | 2 [0-4] [0-9] | 25 [0-5]）$ / 255 /'
 

不过，你可能会做的更好使用 AWK ：

 的awk'/ ^ [0-9] [0-9] * $ / {如果（$ 1 LT = 32）打印32
                       否则如果（$ 1 LT; = 64）打印64
                       否则如果（$ 1 LT = 128）打印128
                       否则如果（$ 1 LT = 255）打印255
                       否则打印$ 1
                       下一个
                     }
     {}打印
 

最后其他子句准确地打印出任何意外的值，如256或999，或者更确切地说，123456789有那些谁这样写 1 在的{打印} - 相匹配，并打印出 AWK 脚本的一部分IP地址。

I need to replace a range of numbers with a certain number. I really tried it hard to code it myself with sed (like sed "s/[33-64]/64/") or awk, but always get wrong results. It tends to replace single digits instead of numbers... What I need would be: Replacing 0-32 -> 32, 33-64 -> 64, 65-128 -> 128, 129-255 -> 255. In between these numbers are IPs, which should stay untouched. I think this command is selecting all, but IPs:

sed '/[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}/! ...  '

So I have a file like this:

65.74.16.161
232
10.128.8.72
63
10.128.14.13
100
10.128.8.58
32
10.128.4.129
60
10.128.240.18
59

and it should look like this:

65.74.16.161
255
10.128.8.72
64
10.128.14.13
128
10.128.8.58
32
10.128.4.129
64
10.128.240.18
64

解决方案

The [33-64] defines a character class and is a funny way of writing [3-6] and does indeed only match a single character — any single digit from 3, 4, 5 or 6. If you really want to do it with sed, and you're concerned with values from 33 to 64, then you have to write it out differently — and much more verbosely.

In part it depends on which version of sed you have. A solution that will work with classic sed is:

sed -e 's/^[0-9]$/32/' \
    -e 's/^[12][0-9]$/32/' \
    -e 's/^3[012]$/32/' \
    -e 's/^3[3-9]$/64/' \
    -e 's/^[45][0-9]$/64/' \
    -e 's/^6[0-4]$/64/' \
    -e 's/^6[5-9]$/128/' \
    -e 's/^[7-9][0-9]$/128/' \
    -e 's/^1[01][0-9]$/128/' \
    -e 's/^12[0-8]$/128/' \
    -e 's/^129$/255/' \
    -e 's/^1[3-9][0-9]$/255/' \
    -e 's/^2[0-4][0-9]$/255/' \
    -e 's/^25[0-5]$/255/'

But, as you can see, it is quite painful. If you have GNU sed, you can use the -r option to enable extended regular expressions; if you have Mac OS X or BSD sed, you can use the -E option to enable extended regular expressions. Then you can reduce the code above to:

sed -E \
    -e 's/^([0-9]|[12][0-9]|3[012])$/32/' \
    -e 's/^(3[3-9]|[45][0-9]|6[0-4])$/64/' \
    -e 's/^(6[5-9]|[7-9][0-9]|1[01][0-9]|12[0-8])$/128/' \
    -e 's/^(129|1[3-9][0-9]|2[0-4][0-9]|25[0-5])$/255/'

However, you might do better using awk:

awk '/^[0-9][0-9]*$/ { if      ($1 <=  32) print  32
                       else if ($1 <=  64) print  64
                       else if ($1 <= 128) print 128
                       else if ($1 <= 255) print 255
                       else                print  $1
                       next
                     }
     { print }'

The final else clause accurately prints any unexpected values, such as 256 or 999 or, indeed, 123456789. There are those who would write 1 in place of { print } — the part of the awk script that matches and prints the IP addresses.

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