Backbone.js的model.save返回类型错误？ [英] Backbone.js model.save returns TypeError?

问题描述

我想实现Backbone.js的模型，看起来像这样在Django：

I'm trying to implement backbone.js model which looks like this in Django:

class Booking(models.Model):
    date        = models.DateField('date booked')
    time        = models.TimeField('time booked')
    duration    = models.PositiveSmallIntegerField('duration booked') #x * 15
    user        = models.ForeignKey(User, related_name='bookings')
    room        = models.ForeignKey(Room, related_name='bookings')
    description = models.TextField()

/ API /预订：

它是经由TastyPie一个RESTful接口服务。
我的骨干模型建立这样按照说明这里：

It's served through a RESTful interface via TastyPie: /api/booking. My backbone model is set up like this as per instructions here:

window.Booking = Backbone.Model.extend({
url     :   function(){
                return this.get('resource_uri') || this.collection.url;
            },
urlRoot :   "/api/booking",
defaults:   {
                user    :   "/api/user/5" //defaults to nobodys
                }
});
window.Bookings = Backbone.Collection.extend({
url         :   BOOKING_API,
parse       :   function(data){
                return data.objects;
            }
});

现在想测试一下控制台是这样的：

Now trying to test it out in console like this:

var booking = new Booking({date : "2011-08-17", time: "12:45", duration: 30, room: "/api/room/1", description: "quickbook"});
booking.save();

以上code返回一个类型错误。我不明白我在做什么错了。

The above code returns a TypeError. I don't see what I'm doing wrong.

推荐答案

您没有定义resource_uri或将预订一个收藏。你所看到的类型错误是this.collection.url。你会看到相同的错误做booking.collection.url。像下面的东西应该做的伎俩。

You are not defining a resource_uri or putting your booking in a collection. The TypeError you are seeing is from this.collection.url. You would see the same error doing booking.collection.url. Something like the following should do the trick.

var bookings = new Bookings;
bookings.add(booking);
booking.save();

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