如何逃脱双引号里面的双引号？ [英] How to escape double quote inside a double quote?

问题描述

有人能告诉我如何逃脱bash中双字符串内双引号？

Can anybody show me how to escape double quote inside a double string in bash?

例如在我的shell脚本

For example in my shell script

#!/bin/bash

dbload="load data local infile \"'gfpoint.csv'\" into table $dbtable FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY \"'\n'\" IGNORE 1 LINES"

我不能封闭BY \\用双引号逃逸正常。我不能用单引号为我的变量，因为我想用变量 $ DBTABLE 。

I can't get the ENCLOSED BY \" with double quote escape correctly. I can't use single quote for my variable because i want to use variable $dbtable.

推荐答案

使用反斜杠：

echo "\""     # Prints one " character.

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