与编写脚本的netcat的HTTP头请求 [英] Scripting an HTTP header request with netcat

问题描述

我试图玩弄netcat来了解更多关于如何HTTP的工作原理。我想脚本一些它在bash或Perl，但我已经在一个绊脚石早就在我的测试击中。

I'm trying to play around with netcat to learn more about how HTTP works. I'd like to script some of it in bash or Perl, but I've hit upon a stumbling block early on in my testing.

如果我在一个HEAD请求作出了迅速和类型的netcat跑直线，它的工作原理和我收到的标头，我探测Web服务器。

If I run netcat straight from the prompt and type in a HEAD request, it works and I receive the headers for the web server I'm probing.

本作品：

    [romandas@localhost ~]$ nc 10.1.1.2 80
    HEAD / HTTP/1.0

    HTTP/1.1 200 OK
    MIME-Version: 1.0
    Server: Edited out
    Content-length: 0
    Cache-Control: public
    Expires: Sat, 01 Jan 2050 18:00:00 GMT

    [romandas@localhost ~]$

但是，当我把同样的内容到一个文本文件，并将其输送到netcat的通过管道或通过重定向，在preparation的脚本，它不会返回头。结果
该文本文件由HEAD请求和两个新行：

But when I put the same information into a text file and feed it to netcat through a pipe or via redirection, in preparation for scripting, it doesn't return the headers.
The text file consists of the HEAD request and two newlines:

HEAD / HTTP/1.0

通过发送相同的信息回声或的printf 也不起作用。

$ printf "HEAD / HTTP/1.0\r\n"; |nc -n 10.1.1.2 80
$ /bin/echo -ne 'HEAD / HTTP/1.0\n\n' |nc 10.1.1.2 80

任何想法，我做错了什么？不知道这是一个bash的问题，回声等问题，或netcat的问题。

Any ideas what I'm doing wrong? Not sure if it's a bash problem, an echo problem, or a netcat problem.

我通过检查Wireshark的交通，并成功申请（手动输入）发送尾随的换行符在第二个数据包，而回声，printf的，和文本文件的方法保持在同一个包中的换行，但我不确定是什么原因导致这种行为。

I checked the traffic via Wireshark, and the successful request (manually typed) sends the trailing newline in a second packet, whereas the echo, printf, and text file methods keep the newline in the same packet, but I'm not sure what causes this behavior.

推荐答案

您需要两批为\\ r \\ n，并且还告诉netcat来等待响应。 printf的HEAD / HTTP / 1.0 \\ r \\ n \\ r \\ n|。NC -n -i 1 10.1.1.2 80 或类似的工作，应

You need two lots of "\r\n", and also to tell netcat to wait for a response. printf "HEAD / HTTP/1.0\r\n\r\n" |nc -n -i 1 10.1.1.2 80 or similar should work.

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