一个接一个（运行）结束开始脚本 [英] Start script after another one (already running) finishes

问题描述

所以我有一个进程在运行，它会需要几个小时才能完成。我想，一个完成后自动启动另一个程序的权利。请注意，我不能在第一个加一个调用第二个脚本，既不创建另一个其中顺序同时运行。有什么办法在Linux下做到这一点？

So I have a process running, and it will take several hours to complete. I would like to start another process right after that one finishes, automatically. Notice that I can't add a call to the second script in the first one, neither create another which sequentially runs both. Is there any way to do this in Linux?

编辑：一种选择是使用指派，轮询间隔 X 分钟检查过程结束。如果那样，开始另一个。但是，我不喜欢这种解决方案。

One option is to poll every x minutes using pgrep and check if the process finished. If it did, start the other one. However, I don't like this solution.

PS：两者都是的bash脚本，如果这能帮助

PS: Both are bash scripts, if that helps.

推荐答案

轮询可能是要走的路，但它并不一定可怕。

Polling is probably the way to go, but it doesn't have to be horrible.

pid=$(ps -opid= -C your_script_name)
while [ -d /proc/$pid ] ; do
    sleep 1
done && ./your_other_script

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