击：用差异的结果，在if语句 [英] Bash: using the result of a diff in a if statement

问题描述

我写一个简单的Bash脚本当文件夹已被修改，以检测。

这是一件很接近：

  LS -lR $ DIR＆GT;一个
LS -lR $ DIR＆GT; bDIFF = $（差异A B）
如果[$ DIFF -ne 0]
然后
    回声目录被修改
 

不幸的是，if语句输出错误：[：-ne：一元运算符预期。

我不知道有什么不对我的脚本，会有人请能帮帮我吗？

非常感谢你！

Jary

解决方案

  LS -lR $ DIR＆GT;一个
LS -lR $ DIR＆GT; bDIFF = $（差异A B）
如果[$ DIFF！=]
然后
    回声目录被修改
科幻
 

I am writing a simple Bash script to detect when a folder has been modified.

It is something very close to:

ls -lR $dir > a
ls -lR $dir > b

DIFF=$(diff a b) 
if [ $DIFF -ne 0 ] 
then
    echo "The directory was modified"

Unfortunately, the if statement prints an error: [: -ne: unary operator expected

I am not sure what is wrong with my script, would anyone please be able to help me?

Thank you very much!

Jary

解决方案

ls -lR $dir > a
ls -lR $dir > b

DIFF=$(diff a b) 
if [ "$DIFF" != "" ] 
then
    echo "The directory was modified"
fi

这篇关于击：用差异的结果，在if语句的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！