BASH：getopts的从一个标志检索多个变量 [英] BASH: getopts retrieving multiple variables from one flag

问题描述

我卡住，需要你的帮助球员与getops

I am stuck and need your guys help with with getops

我创建了一个bash脚本运行时，它看起来像这样：

I created a bash script which looks like this when run:

$ foo.sh -i ENV -d目录-s -f子目录文件

$ foo.sh -i env -d directory -s subdirectory -f file

处理来自各个标志一个参数，当它正常工作。但是，当我envoke几个arguements从每个标志我不知道如何把多个varibale信息出变量的getops。

It works correctly when handling one argument from each flag. But when I envoke several arguements from each flag I am not sure how to pull the multiple varibale information out of the variables in getops.

while getopts ":i:d:s:f:" opt
   do
     case $opt in
        i ) initial=$OPTARG;;
        d ) dir=$OPTARG;;
        s ) sub=$OPTARG;;
        f ) files=$OPTARG;;

     esac
done

抓住选项后，我再想从变量建立目录结构

After grabbing the options I then want to build directory structures from the variables

foo.sh -i test -d directory -s subdirectory -s subdirectory2 -f file1 file2 file3

接着的目录结构将是

Then the directory structure would be

/test/directory/subdirectory/file1
/test/directory/subdirectory/file2
/test/directory/subdirectory/file3
/test/directory/subdirectory2/file1
/test/directory/subdirectory2/file2
/test/directory/subdirectory2/file3

任何想法？

推荐答案

您可以使用同一选项多次和所有值添加到一个数组

对于这里的非常具体的原题，瑞安的的mkdir -p 解决方案显然是最好的。

For the very specific original question here, Ryan's mkdir -p solution is obviously the best.

不过，对于更一般的问题的从getopts的同一选项越来越多的价值观，那就是：

However, for the more general question of getting multiple values from the same option with getopts, here it is:

#!/bin/bash

while getopts "m:" opt; do
    case $opt in
        m) multi+=("$OPTARG");;
        #...
    esac
done
shift $((OPTIND -1))

echo "The first value of the array 'multi' is '$multi'"
echo "The whole list of values is '${multi[@]}'"

echo "Or:"

for val in "${multi[@]}"; do
    echo " - $val"
done

将输出：

$ /tmp/t
The first value of the array 'multi' is ''
The whole list of values is ''
Or:

$ /tmp/t -m "one arg with spaces"
The first value of the array 'multi' is 'one arg with spaces'
The whole list of values is 'one arg with spaces'
Or:
 - one arg with spaces

$ /tmp/t -m one -m "second argument" -m three
The first value of the array 'multi' is 'one'
The whole list of values is 'one second argument three'
Or:
 - one
 - second argument
 - three

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