在bash字符串比较。 [[： 未找到 [英] String comparison in bash. [[: not found

问题描述

我想在bash比较字符串。我已经找到了如何做到这一点的计算器的答案。在剧本我想，我现在用在提到的问题提交亚当code：

I am trying to compare strings in bash. I already found an answer on how to do it on stackoverflow. In script I am trying, I am using the code submitted by Adam in the mentioned question:

#!/bin/bash
string='My string';

if [[ "$string" == *My* ]]
then
  echo "It's there!";
fi

needle='y s'
if [[ "$string" == *"$needle"* ]]; then
  echo "haystack '$string' contains needle '$needle'"
fi

我也尝试从 ubuntu论坛的方法，你可以在第二后发现

I also tried approach from ubuntuforums that you can find in 2nd post

if [[ $var =~ regexp ]]; then
  #do something
fi

在这两种情况下，我收到错误：

In both cases I receive error:

[[: not found

我在做什么错了？

What am I doing wrong?

推荐答案

[是一个bash，内置。你的 /斌/庆典似乎并没有一个实际的bash。

[[ is a bash-builtin. Your /bin/bash doesn't seem to be an actual bash.

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