脏变 - 删除回车 [英] Dirty Variable - Remove Carriage return

问题描述

我有以下变量。

 回声| $ COMMAND |
 

返回

  |
REBOOT |
 

我怎样才能删除第一个回车？

解决方案

 回声| $ COMMAND || TR的'\\ n'''
 

将取代换行符（POSIX中/ Unix上它不是一个回车）有一个空格。

说实话，我会考虑从bash的切换虽然客场东西更理智。或避免在首位产生这种畸形数据。

嗯，这个，好像它可能是一个可怕的安全漏洞以及具体情况取决于数据的来源。

I have the following variable.

echo "|$COMMAND|"

which returns

|
REBOOT|

How can i remove that first carriage return ?

解决方案

echo "|$COMMAND|"|tr '\n' ' '

will replace the newline (in POSIX/Unix it's not a carriage return) with a space.

To be honest I would think about switching away from bash to something more sane though. Or avoiding generating this malformed data in the first place.

Hmmm, this seems like it could be a horrible security hole as well, depending on where the data is coming from.

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