插入符搜索和Bash shell中替换 [英] Caret search and replace in Bash shell

问题描述

如果我刚才在猛砸输入以下命令：

If I have just entered the following command in Bash:

echo foo

我可以改变美孚通过打字吧：

I can change foo to bar by typing:

^foo^bar

这导致下面的命令被执行：

Which results in the following command being executed:

echo bar

现在，如果我输入：

echo foo foo

有没有办法来改变富的两个实例通过使用插入符号（ ^ ）运算符？

此外，还有手册页外壳运营商如 ^ ？ ^人的结果的^无需人工录入。

Additionally, are there man pages for shell operators like ^? man ^ results in "No manual entry for ^".

推荐答案

这特定的功能被称为的快速替换的;它的文档可以在Bash手册的事件标志部分找到。你不能做你想要快速替换的东西;你得稍微详细诉诸东西：

That particular feature is called quick substitution; its documentation can be found in the Event Designators section of the Bash Manual. You can't do what you want with quick substitution; you'll have to resort to something slightly more verbose:

!!:gs/foo/bar/

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