巴什间接引用,其中一个变种引用多个 [英] Bash indirect reference where one var references multiple
问题描述
我试图取消引用两个或包含在一个单一变量更多的变量,但我想不出如何做到这一点不EVAL:
I am trying to dereference two or more variables contained in a single variable but I can't think of how to do it without eval:
$:b=5
$:c=10
$:a='$b $c'
$:result=`eval echo $a`
$:echo $result
5 10
我希望做的相当的操作,让我'结果',所以我没有做一个eval。是否有可能解决由单一变量任何其他方式引用多个变量?我要做到这在bash
I'm looking to do the equivalent operation that gives me 'result' so I don't have to do an eval. Is it possible to resolve multiple variables referenced by a single variable any other way? I'm looking to do this in BASH
推荐答案
EVAL听起来挺吓人的......
eval sound quite scary...
这里是一个更好的解决方案:
here is a better solution:
<一个href=\"http://stackoverflow.com/questions/2914220/bash-templating-how-to-build-configuration-files-from-templates-with-bash\">Bash模板:怎样从猛砸模板建立配置文件
您只需要调整它了一点,所以它遵循你的语法。
you just have to tweak it a bit so it follows your syntax.
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