如何输出文件名与单线引号包围？ [英] how to output file names surrounded with quotes in SINGLE line?

问题描述

我想在如下因素的方式输出文件夹中的项目清单：

I would like to output the list of items in a folder in the folowing way:

"filename1"  "filename2" "file name with spaces" "foldername" "folder name with spaces"

在换句话说，项目名称必须是单行线，通过空格用引号（单人或双人）包围并分割。

In other words, item names must be in a single line, surrounded with quotes (single or double) and divided by spaces.

我知道

find . | xargs echo

打印输出在一个单一的线，但我不知道如何添加各地的各项目名的报价。

prints output in a single line, but I do not know how to add quotes around each item name.

这code是BSH脚本的一部分。
因此，该解决方案可以是一组命令和使用的临时文件，用于存储中间输出

This code is part of a bsh script. The solution can therefore be a set of commands and use temporary files for storing intermediate output.

非常感谢您的任何建议。

Thank you very much for any suggestion.

干杯，安娜

推荐答案

这应该工作

find $PWD | sed 's/^/"/g' | sed 's/$/"/g' | tr '\n' ' '

编辑：

此应大于previous多一个高效

This should be more efficient than the previous one.

find $PWD | sed -e 's/^/"/g' -e 's/$/"/g' | tr '\n' ' '

@ Timofey的溶液将与在端部的TR工作，应是最有效的。

@Timofey's solution would work with a tr in the end, and should be the most efficient.

find $PWD -exec echo -n '"{}" ' \; | tr '\n' ' '

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