我如何拆分和QUOT; ABCD EFGH＆QUOT;进入＆QUOT; ABCD＆QUOT;和＆QUOT; EFGH＆QUOT;？ [英] How do I split "abcd efgh" into "abcd" and "efgh"?
问题描述
这是真正的自我解释。我在bash shell中工作，我真正的新Shell脚本。我发现了很多有关使用 TR 和 SED ，但所有的例子我已经发现迄今卸下分隔符和新行。我真正想要做的是相反的。我希望能够以一个空格分隔。我有一个像ABCD EFGH的字符串，我需要它是ABCD，EFGH（所有不带引号，只是为了显示分组）。
This is really self explanatory. I'm working in a bash shell and I'm really new to shell scripting. I've found a lot of information about using tr and sed but all the examples I have found so far are removing delimiters and new lines. I really want to do the opposite of that. I want to be able to separate based on a blank space. I have a string like "abcd efgh" and I need it to be "abcd" "efgh" (all without quotes, just to show groupings).
我敢肯定，这是简单得多比我做的，但我很困惑。
I'm sure this is much simpler than I'm making it, but I'm very confused.
更新问题：
我有已投入的阵列的PID的一列，但该阵列的每个元素有两个在列的PID。
I have a column of PIDs that I have put into an array, but each element of the array has both the pids in the column.
列：
1234
5678
当我打印出整个阵列，所有的不同列已被添加，所以我所有的值，但是当我打印出我的数组的单个元素我得到的是这样的：
when I print out the entire array, all the different columns have been added so I have all the values, but when I print out a single element of my array I get something like:
1234 5678
这不是我想要的。
我需要为1234和元素单独一个5678。
which is not what I want. I need to have an element for 1234 and a separate one for 5678.
这是我的code迄今：
This is my code so far:
!/bin/bash
echo "Enter the File Name"
read ips
index=0
IFS=' '
while read myaddr myname; do
myips[$index]="$myaddr"
names[$index]="$myname"
index=$(($index+1))
done < $ips
echo "my IPs are: ${myips[*]}"
echo "the corresponding names are: ${names[*]}"
echo "Total IPs in the file: ${index}"
ind=0
for i in "$myips[@]}"
do
echo $i
pids=( $(jps | awk '{print $1}') )
for pid in "${pids[@]}"; do
echo $pid
done
echo "my PIDs are: ${pids}"
for j in "${pids[@]}"
do
mypids[$ind]="$j"
ind=$(($ind+1))
done
done
echo "${mypids[*]}"
echo "The 3rd PID is: ${mypids[2]}"
输出示例：
Total IPs in the file: 6
xxx.xxx.xxx.xxx
5504
1268
1
xxx.xxx.xxx.xxx
5504
4352
1
xxx.xxx.xxx.xxx
5504
4340
1
5504
1268 5504
4352 5504
4340
The 3rd pid is: 5504
4340
我需要每个PID是分开的，使得数组的每个元素，是单个的pid。因此，例如，行第三pid是：需要看起来像
I need each pid to be separate, so that each element of the array, is a single pid. So for instance, the line "The 3rd pid is: " needs to look something like
The 3rd pid is: 5504
和第四要素是4340
and the 4th element would be 4340
推荐答案
尝试 剪切 ：
$ echo "abcd efgh" | cut -d" " -f1
abcd
$ echo "abcd efgh" | cut -d" " -f2
efgh
另外，如果在某些时候你想要做的事比较复杂，不考虑 AWK 还有：
$ echo "abcd efgh" | awk '{print $1}'
abcd
$ echo "abcd efgh" | awk '{print $2}'
efgh
要解决你的问题的更新：
To address your updated question:
我有已投入的阵列的PID的一列，但该阵列的每个元素有两个在列的PID。
I have a column of PIDs that I have put into an array, but each element of the array has both the pids in the column.
如果你想一列数据加载到一个数组，你可以做这样的事情：
If you want to load a column of data into an array, you could do something like this:
$ pgrep sshd # example command. Get pid of all sshd processes
795
32046
32225
$ A=(`pgrep sshd`) # store output of command in array A
$ echo ${A[0]} # print first value
795
$ echo ${A[1]} # print second value
32046
到C您发布，有关问题的原因是，你已经变 $ IFS 来一个空格（解决例如$ C $ IFS =''），这意味着这是由换行符分隔的列不再被拆分。
To address the example code you posted, the reason for your problem is that you've change $IFS to a space (IFS=' ') which means that your columns which are separated by newlines are no longer being split.
考虑这个例子：
$ A=(`pgrep sshd`)
$ echo ${A[0]} # works as expected
795
$ IFS=' ' # change IFS to space only
$ A=(`pgrep sshd`)
$ echo ${A[0]} # newlines no longer used as separator
795
32046
32225
要避免这个问题，通常的做法是始终备份原始 IFS 并更换一旦你使用更新后的值来完成。例如。
To avoid this problem, a common approach is to always backup the original IFS and replace it once you've done using the updated value. E.g.
# backup original IFS
OLDIFS=$IFS
IFS=' '
# .. do stuff ...
# restore after use
IFS=$OLDIFS
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