在bash脚本标准错误的临时重定向 [英] Temporary redirection of stderr in a bash script

问题描述

我有一个用于启动其他程序的简单脚本。这其他程序有时可能会产生一个 SIGSEGV ，扰乱我的输出。因此，我增加了几个这是应该暂时重定向标准错误到的/ dev / null的使得线 SIGSEGV 被忽略。以下是我的code的草稿：

I have a simple script which is used to start another program. This other program may sometimes yield a SIGSEGV, which disrupts my output. I have therefore added a couple of lines which is supposed to temporarily redirect the stderr to /dev/null such that the SIGSEGV is ignored. The following is a draft of my code:

exec 2> /dev/null
progname >& ./tmp/run.txt && run_status='OK'
exec 2>1

问题是，最后一行没有做我想做的。第一行显然工程，并重定向标准错误。最后一行应该返回标准错误回其原来的位置（我只应该是一样的标准输出）。

The problem is that the last line does not do what I want. The first line obviously works, and redirects the stderr. The last line is supposed to return the stderr back to where it was before (which I have only supposed is the same as stdout).

任何帮助将appriciated！

Any help would be appriciated!

推荐答案

另外一个选择是：

exec 3> /dev/stderr 2> /dev/null
progname >& ./tmp/run.txt && run_status='OK'
exec 2>&3

甚至

exec 3>&2 2> /dev/null
progname >& ./tmp/run.txt && run_status='OK'
exec 2>&3

这样的脚本preserves输出和错误的脚本（分离即脚本stdout和stderr可以单独进行重定向。

That way the script preserves the separation of stdout and stderr for the script (ie. the scripts stdout and stderr can be redirected separately.

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