我怎样才能逃避正斜杠在用户输入变量在bash？ [英] How can I escape forward slashes in a user input variable in bash?

问题描述

我工作的一个脚本，以建立一个网站Statamic更有效。我遇到的问题是，可变我使用替换文件中的字符串已经转义正斜杠，是用户输入。我怎样才能确保 _site_url：http://statamic.com 将成为 _site_url：http://example.com ？

下code将工作只要没有斜杠present。

 回声什么是你的网站的网址，不要忘了协议？！（如HTTP：//）
阅读-e SITE_URL回声％s / _site_url：HTTP：\\ / \\ / statamic.com/_site_url：$ SITE_URL / G
W¯¯
q
|恩_config / settings.yaml
 

解决方案

问题是在你的前命令的分隔符。我们可以把任何东西，我们希望不是，我用 @ 这里：

试着这样做：

  SED -iS @ _site_url：http://statamic.com/_site_url：$ @ SITE_URL G_config / settings.yaml
 

或与前命令：

 回声什么是你的网站的网址，不要忘了协议？！（如HTTP：//）
阅读-e SITE_URL回声％S @ _site_url：HTTP：//statamic.com@_site_url：$ @ SITE_URL摹
W¯¯
q
|恩_config / settings.yaml
 

I'm working on a script to make setting up a Statamic site more efficient. The problem I'm running into is that the variable I'm using to replace a string in a file has unescaped forward slashes and is user input. How can I make sure that _site_url: http://statamic.com will become _site_url: http://example.com?

The code below will work as long as there are no forward slashes present.

echo "What's your site URL? Don't forget the protocol (ex. http://)!"
read -e SITE_URL

echo "%s/_site_url: http:\/\/statamic.com/_site_url: $SITE_URL/g
w
q
" | ex _config/settings.yaml

解决方案

The problem is the delimiter in your ex command. We can put anything we'd like instead, I use @ here :

Try doing this :

 sed -i "s@_site_url: http://statamic.com/_site_url: $SITE_URL@g" _config/settings.yaml

Or with your ex command :

echo "What's your site URL? Don't forget the protocol (ex. http://)!"
read -e SITE_URL

echo "%s@_site_url: http://statamic.com@_site_url: $SITE_URL@g
w
q
" | ex _config/settings.yaml

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