需要帮助的bash脚本替换单引号 [英] Need help replacing single quotes in bash script

问题描述

我试图替换字符串中的引号在我的bash脚本。我有一个将被放置在一个MySQL查询有可能有一个单引号中有一个变量。我想更换任何 与 \\ ，所以我可以逃脱的任何报价，而不是搞砸了我的查询。

我想这是一个测试，但它不工作：

 文本=Bobby的测试
回声$ {文/＃'/ \\\\\\'}
 

我究竟做错了或有甚至是更好的办法做到这一点，我还没有想过？我preFER不具备使用sed或任何东西为好。

解决方案

回声$ {//文\\'/ \\ '}


请确保您使用在外面的双引号，否则你将需要更多的转义（啊）。

i am trying to replace the quotes in a string in my bash script. i have a variable that will be placed in a mysql query that may possibly have a single quote in it. i want to replace any ' with \' so i can escape any quote and not screw up my query.

i tried this as a test but it doesn't work:

text="bobby's test"
echo ${text/#'/\\\'}

what am i doing wrong or is there even a better way to do this that i havent thought of? i prefer to not have to use sed or anything as well.

解决方案

echo "${text//\'/\'}"

Make sure you use the double quotes on the outside, or you are going to need more escaping (ugh).

这篇关于需要帮助的bash脚本替换单引号的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！