Windows 7的批处理脚本'为'命令错误/缺陷 [英] Windows 7 Batch Script 'For' Command Error/Bug

问题描述

有似乎是'为'命令的Windows 7的批处理文件中的错误。该命令可以通过源目录走路，在同一时间返回1名。但我发现，如果我的命令来修改该源目录例如文件。

There seems to be a bug with the Windows 7 batch file 'for' command. This command can walk through a source directory and return one filename at a time. But I found that if my command modify the files in that source directory e.g.

for /R %1 %%s in (*.*) do call :do1file %%s
@goto :EOF

:do1file 
@echo es > tmp_x2932.tmp
move /y tmp_x2932.tmp  %1
@goto :EOF

在'为'命令可以使用​​相同的文件名超过1倍以上调用做命令。 （需要注意的是，为了说明这个问题，目的的回响ES> tmp_x2932.tmp'只是一个简单的替换其他一些合法的命令，如sed的，即编辑原始的源文件。）

the 'for' command could invoke the do command with the same file name more than 1 times. (Note that, for the purpose of illustrating the issue, the 'echo es > tmp_x2932.tmp' is just a simple replacement of some other legitimate command, like 'sed', that edit the original source file.)

例如，9个文件的目录

D:\build-release\dump>dir /on
 Volume in drive D has no label.
 Volume Serial Number is 1972-268D

 Directory of D:\build-release\dump

12/03/2011  05:13 PM    <DIR>          .
12/03/2011  05:13 PM    <DIR>          ..
12/03/2011  05:40 PM                 5 f1
12/03/2011  05:40 PM                 5 f2
12/03/2011  05:40 PM                 5 f3
12/03/2011  05:40 PM                 5 f4
12/03/2011  05:40 PM                 5 f5
12/03/2011  05:40 PM                 5 f6
12/03/2011  05:40 PM                 5 f7
12/03/2011  05:40 PM                 5 f8
12/03/2011  05:40 PM                 5 f9
               9 File(s)             45 bytes
               2 Dir(s)  31,200,313,344 bytes free

会产生这样的结果（testdir.bat使用批处理文件名）：

will produce this result (testdir.bat is the batch file name used):

d:\test>testdir D:\build-release\dump
d:\test>for /R D:\build-release\dump %s in (*.*) do call :do1file %s
d:\test>call :do1file D:\build-release\dump\f4
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f4
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f5
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f5
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f6
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f6
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f7
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f7
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f8
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f8
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f9
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f9
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f1
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f1
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f2
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f2
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f3
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f3
        1 file(s) moved.
d:\test>call :do1file D:\build-release\dump\f4
d:\test>move /y tmp_x2932.tmp  D:\build-release\dump\f4
        1 file(s) moved.

文件D：\\ build中释放\\转储\\ F4被称为错误地两次

file D:\build-release\dump\f4 is called twice erroneously.

此行​​为不是在Windows XP中观察到。有什么办法解决它在Windows 7中不改变老段子？我知道我可以一直使用的临时目录中，而不是存储在地方修改它们的所有中间文件，但我的老段子在Windows XP只是做到这一点。

This behaviour is not observed in Windows XP. Is there any way to fix it in Windows 7 without changing the old scripts? I know I can always use a temporary directory to store all the intermediate files instead of modifying them in place, but my old scripts in Windows XP just do that.

推荐答案

到目前为止，我只能建议更换 FOR / R 循环与 FOR /˚F使用 DIR / S 输出：

So far I can only suggest replacing the FOR /R loop with FOR /F that uses the output of DIR /S:

FOR /F "delims=" %%s IN ('DIR %1 /S /B') DO CALL :do1file %%s
…

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