根据文件内容批处理文件重命名文件 [英] Rename file based on file Content batch file

问题描述

我需要一个批处理文件，读取该文件xyz.txt将该描述名称present和基于描述名称重命名文件名。

I need a batch file that reads the description name present in the XYZ.txt file and rename that file name based on description name.

例如，我有所谓的nest.txt的文件名，当我们打开文本文件（nest.txt）的文件名的第二行有描述（description =人），那么这个批处理文件应该重命名我的XYZ .txt文件作为Man.txt

For example i have a file name called "nest.txt" and when we open the text file(nest.txt) the second line of the file name has Description(Description=Man) then the batch file should rename my XYZ.txt file as Man.txt

我有1000个文件，根据上述条件进行重命名。请帮我

i have 1000 files to rename based on the above condition. Please help me

推荐答案

试试这个：

for /f "skip=1 tokens=1* delims==" %%i in (nest.txt) do ren XYZ.txt "%%~j.txt"

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