切在Windows相当于 [英] cut equivalent in Windows

问题描述

我也有条目下面的文件。

  / A / B / C / D / E / F
/ A / B / C / G / K / L / F / J / h的
/ A / B / C / I / M / N / P
 

我需要在Windows命令将其删除/ A / B / C部分从文件。

输出文件应该看起来像

D / E / F
 克/ K / L / F / J / h的
 I / M / N / P

我尝试使用与命令/作为分隔符，但不能得到预期的结果。
任何人都可以请帮助？

解决方案

 关闭@echo（FOR / F令牌= 3，* delims = /%%一中（input.txt中）做回声%% B）＆GT; output.txt的
 

和的绝招是问第三令牌和行的其余部分。

要直接在命令行中使用它。

 （FOR / F令牌= 3，* delims = /，在（input.txt中）做@echo％B％A）GT; output.txt的
 

转义百分号简化工作，并从命令行呼应了默认不启用， @ 在回声需要

I have a file which has entries as below.

/a/b/c/d/e/f
/a/b/c/g/k/l/f/j/h
/a/b/c/i/m/n/p

I need a command in windows which would remove the '/a/b/c' part from the file.

The output file should look like

d/e/f g/k/l/f/j/h i/m/n/p

I tried using for command with / as delimiter, but couldn't get the expected result. can anyone please help?

解决方案

@echo off

(for /f "tokens=3,* delims=/" %%a in (input.txt) do echo %%b) > output.txt

And the "trick" is to ask for the third token and the rest of the line.

To use it directly from command line

(for /f "tokens=3,* delims=/" %a in (input.txt) do @echo %b) > output.txt

The escaped percent signs are simplified and, as from command line the echo off is not enabled by default, the @ before echo is needed

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