如何转移参数在批处理文件时，有超过10个参数 [英] How to shift arguments in batch files when there are more than 10 arguments

问题描述

我正在学习如何使用VBScript的像本地脚本语言编写批处理文件为Windows 7。

I am learning how to write batch files for Windows 7 using the VBScript like native scripting language.

我想我没有使用Windows脚本主机或电源外壳。我使用简单的旧式的VBScript的语法。

I suppose I am not using the Windows Scripting Host or the Power Shell. I am using the simple old style VBScript like syntax.

我不明白如何转移的参数时，有超过9参数（或10包括批处理文件的名称）传递给该批处理文件。

I don't understand how to shift arguments when there are more than 9 arguments (or 10 including the name of the batch file) passed to the batch file.

你能教教我吗？

让我们假设你调用下面的参数我的批处理文件：

Let us assume that you called my batch file with the following arguments:

C:\>call my.bat "one" "two" "three" "four" 
    "five" "six" "seven" "eight" "nine" "ten" "eleven"

您将如何访问这些参数 10 和十一从内部 my.bat ？

How would you access the arguments ten and eleven from within my.bat?

推荐答案

这是从ss64.com

this is the batch taken from ss64.com

@echo off
:start
if "%1"=="" (goto :exit)
:: Do whatever with token %1
Echo [%1] 
:: Shift %2 into %1 
SHIFT
goto :start

:exit
::pause

调用批处理有超过10个参数，它会显示所有的

call that batch with more than 10 arguments, it will display all

    shift.bat 1 2 3 4 5 6 7 8 9 10 11
[1]
[2]
[3]
[4]
[5]
[6]
[7]
[8]
[9]
[10]
[11]

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