CMD批处理文件丢失员错误 [英] CMD Batch File Missing Operator Error

问题描述

获得第3行一个缺少操作员错误执行在DOS批处理文件中的以下时 - 所以第二个变量结束了零 - 为什么会这样

  SET VAR1 = 0.3
ECHO％VAR1％
SET / A VAR2 = 2 *％VAR1％
ECHO％VAR2％
 

解决方案

这是因为设置/ A 只能与整数工作。这点，那废墟你的语法。

作为一种解决方法，你可以使用（与大的数字）：

  SET VAR1 = 3/10
ECHO％VAR1％
SET / A VAR2 = 200 *％VAR1％
ECHO％VAR2％
 

这确实设置/一VAR2 = 200 * 3/10

注：为设置/ A 计算与只能为整数， 2 * 0.3 = 2 * 3/10 = 0.6 为您提供 0 只（不四舍五入，只是切割）

Getting a 'missing operator' error on line 3 when executing the following in a DOS batch file - so the second variable ends up as zero - why is this so?

SET VAR1=0.3
ECHO %VAR1%
SET /A VAR2=2*%VAR1%
ECHO %VAR2%

解决方案

that's because set /a can work with integers only. It's the dot, that ruins your Syntax.

As a Workaround, you can use (with "big" numbers):

SET VAR1=3/10
ECHO %VAR1%
SET /A VAR2=200*%VAR1%
ECHO %VAR2%

That does set /a VAR2=200*3/10

Note: as set /a calculates with integers only, 2*0.3 = 2*3/10 = 0.6 gives you 0 only (no rounding, just cutting)

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