为什么无符号整数X = -1，INT Y =〜0具有相同的二进制重新presentation？ [英] Why do unsigned int x = -1 and int y = ~0 have the same binary representation?

问题描述

在以下code段将是什么：

In the following code segment what will be:

• 函数的结果


• X
价值

• Y的值

    {
         unsigned int x=-1;
         int y;
         y = ~0;
         if(x == y)
             printf("same");
         else
             printf("not same");
     }

a. same, MAXINT, -1
b. not same, MAXINT, -MAXINT
c. same , MAXUINT, -1
d. same, MAXUINT, MAXUINT
e. not same, MAXINT, MAXUINT

有人能解释我如何其作品或者可以只解释片段??

Can someone explain me how its works or can just explain the snippet??

我知道这是关于补ñ等。
什么是MAXINT和-1的意义是什么？
正是由于unsigned int类型和INT的事情 - 我说的对

I know it's about two's complement n etc.. What is the significance of MAXINT and -1 ? It is because of unsigned int and int thing - am I right ?

推荐答案

如果你运行这个程序，你会看到答案一个是的错误的和C是正确答案：

If you run this program, you will see that the answer a is wrong and c is the correct answer:

#include <stdio.h>
#include <limits.h>

int main() {
    unsigned int x=-1;
    int y;
    y = ~0;
    if(x == y)
        printf("same\n");
        if(x==INT_MAX) printf("INT_MAX\n");
        if(x==UINT_MAX) printf("UINT_MAX\n");
    else
        printf("not same");
    return 0;
}

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