二进制补码在Python？ [英] Two's Complement Binary in Python?

问题描述

在Python整数储存在两个补，是否正确？

虽然

 ＆GT;＆GT;＆GT; X = 5
＆GT;＆GT;＆GT;斌（X）
0b101时
 

和

 ＆GT;＆GT;＆GT; X = -5
＆GT;＆GT;＆GT;斌（X）
-0b101
 

这是pretty跛。我如何获得蟒蛇给我的号码REAL二进制位，并没有0B盈呢？所以：

 ＆GT;＆GT;＆GT; X = 5
＆GT;＆GT;＆GT;斌（X）
0101
＆GT;＆GT;＆GT; Y = -5
＆GT;＆GT;＆GT;斌（Y）
1011
 

解决方案

不知道如何得到你想要使用标准库的内容。有脚本和包的少数在那里，会做转换为你。

我只是想说明为什么，为什么它不是跛。

斌（）不返回二进制位。将其转换为二进制字符串的数目。领先的0B告诉你处理的二进制数，按Python语言定义的相互preTER。这种方式，您可以直接与二进制数的工作，像这样

 ＆GT;＆GT;＆GT; 0B01
1
＆GT;＆GT;＆GT; 0b10
2
＆GT;＆GT;＆GT; 0b11
3
＆GT;＆GT;＆GT; 0B01 + 0b10
3
 

这不是跛。这是伟大的。

---

<一个href=\"http://docs.python.org/library/functions.html#bin\">http://docs.python.org/library/functions.html#bin

  

斌（X）

  
  

    

转换的整数为二进制字符串。

  

<一个href=\"http://docs.python.org/reference/lexical_analysis.html#integers\">http://docs.python.org/reference/lexical_analysis.html#integers

  

整数和长整型常量由以下词法定义描述：

  
  

    

bininteger :: =0（b的|B）bindigit +

    
    

bindigit :: =0| 1

  

Integers in Python are stored in two's complement, correct?

Although:

>>> x = 5
>>> bin(x)
0b101

And:

>>> x = -5
>>> bin(x)
-0b101

That's pretty lame. How do I get python to give me the numbers in REAL binary bits, and without the 0b infront of it? So:

>>> x = 5
>>> bin(x)
0101
>>> y = -5
>>> bin(y)
1011

解决方案

Not sure how to get what you want using the standard lib. There are a handful of scripts and packages out there that will do the conversion for you.

I just wanted to note the "why" , and why it's not lame.

bin() doesn't return binary bits. it converts the number to a binary string. the leading '0b' tells the interpreter that you're dealing with a binary number , as per the python language definition. this way you can directly work with binary numbers, like this

>>> 0b01
1
>>> 0b10
2
>>> 0b11
3
>>> 0b01 + 0b10
3

that's not lame. that's great.

---

http://docs.python.org/library/functions.html#bin

bin(x)

Convert an integer number to a binary string.

http://docs.python.org/reference/lexical_analysis.html#integers

Integer and long integer literals are described by the following lexical definitions:

bininteger ::= "0" ("b" | "B") bindigit+

bindigit ::= "0" | "1"

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