二进制字符串为十六进制的Java [英] String binary to Hex Java

问题描述

我有code，看起来像这样

i have code that looks like this

             public static void main(String[] args) {
    String string= "11011100010000010001000000000000";
   String string1= "00000000010000110000100000101100";

    System.out.println(Integer.toHexString(Integer.parseInt(string1,2)));

    System.out.println(Integer.toHexString(Integer.parseInt(string,2)));


}

第一个字符串转换得很好，但第二个具有java.lang.NumberFormatException的错误
不知道是什么问题。

the first string convert just fine but the second one has an error of java.lang.NumberFormatException dont know what the problem is

推荐答案

在32个字符的二进制数的最显著位设置为 1 ，结果值超出 INT 支持的正数的范围，再也不能PTED为有效整数间$ p $。这将导致根据文档除外：

When the most significant bit of a 32-character binary number is set to 1, the resultant value exceeds the range of positive numbers supported by int, and can no longer be interpreted as a valid integer number. This causes the exception according to the documentation:

NumberFormatException类型的异常如果发生下列情况时抛出：

An exception of type NumberFormatException is thrown if any of the following situations occurs:

  
• 第一个参数是null或零长度的字符串。

  
• 的基数可以是小于Character.MIN_RADIX，或大于Character.MAX_RADIX。

  
• 字符串的任何字符不是指定基数的数字，除非第一个字符是减号' - '（'\\ u002D'）为提供的字符串比长1长
。
  
• 由字符串psented转口货值为$ P $不是int类型的值。（重点是我的）

  

• The first argument is null or is a string of length zero.
• The radix is either smaller than Character.MIN_RADIX or larger than Character.MAX_RADIX.
• Any character of the string is not a digit of the specified radix, except that the first character may be a minus sign '-' ('\u002D') provided that the string is longer than length 1.
• The value represented by the string is not a value of type int. (emphasis is mine)

为了进入这个负二进制值，使用 - 在您的号码前符号，其余位转换成2的补再presentation。

In order to enter this negative binary value, use - sign in front of your number, and convert the remaining bits to 2-s complement representation.

如果您需要长度超过32位，或者如果您想值继续成为PTED为正数间$ P $，你需要切换到64位整数数据类型的数字。

If you need numbers that are longer than 32 bits, or if you would like the value to continue being interpreted as a positive number, you would need to switch to the 64-bit integer data type.

这篇关于二进制字符串为十六进制的Java的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！