LockBits图像旋转方法不工作？ [英] LockBits image rotation method not working?

问题描述

嘿所有。我使出使用LockBits二维位图图像旋转厌烦了两种获取/设置像素，并且RotateTransfom的性能下降和古怪的行为之后。因此，这里是code，我拿出，并通过我的推算，应该很好地工作。事实并非如此。

Hey all. I resorted to using LockBits for 2d bitmap image rotation after getting fed up with the slow performance and wacky behavior of both Get/Set Pixel, and RotateTransfom. So here is the code I've come up with, and by my reckoning, it should work perfectly. It doesn't.

private static void InternalRotateImage(Bitmap originalBitmap, Bitmap rotatedBitmap, PointF centerPoint, float theta)
    {
        BitmapData originalData = originalBitmap.LockBits(
            new Rectangle(0, 0, originalBitmap.Width, originalBitmap.Height),
            ImageLockMode.ReadOnly,
            originalBitmap.PixelFormat);

        BitmapData rotatedData = rotatedBitmap.LockBits(
            new Rectangle(0, 0, rotatedBitmap.Width, rotatedBitmap.Height),
            ImageLockMode.WriteOnly,
            rotatedBitmap.PixelFormat);

        unsafe
        {
            byte[,] A = new byte[originalData.Height * 2, originalBitmap.Width * 2];
            byte[,] R = new byte[originalData.Height * 2, originalBitmap.Width * 2];
            byte[,] G = new byte[originalData.Height * 2, originalBitmap.Width * 2];
            byte[,] B = new byte[originalData.Height * 2, originalBitmap.Width * 2];

            for (int y = 0; y < originalData.Height; y++)
            {
                byte* row = (byte*)originalData.Scan0 + (y * originalData.Stride);
                for (int x = 0; x < originalData.Width; x++)
                {
                    B[y, x] = row[x * 4];
                    G[y, x] = row[x * 4 + 1];
                    R[y, x] = row[x * 4 + 2];
                    A[y, x] = row[x * 4 + 3];
                }
            }

            for (int y = 0; y < rotatedData.Height; y++)
            {
                byte* row = (byte*)rotatedData.Scan0 + (y * rotatedData.Stride);
                for (int x = 0; x < rotatedData.Width; x++)
                {
                    int newy = (int)Math.Abs((Math.Cos(theta) * (x - centerPoint.X) - Math.Sin(theta) * (y - centerPoint.Y) + centerPoint.X));
                    int newx = (int)Math.Abs((Math.Sin(theta) * (x - centerPoint.X) + Math.Cos(theta) * (y - centerPoint.Y) + centerPoint.Y));

                    row[x * 4] = B[newy, newx];
                    row[x * 4 + 1] = G[newy, newx];
                    row[x * 4 + 2] = R[newy, newx];
                    row[x * 4 + 3] = A[newy, newx];
                }
            }

        }
            originalBitmap.UnlockBits(originalData);
            rotatedBitmap.UnlockBits(rotatedData);
        }

任何人有什么想法？我新鲜出炉。在此先感谢！

Anybody got any ideas? I'm fresh out. Thanks in advance!

编辑：
这是我最终使用（非常感谢汉斯帕桑特）：

This is what I ended up using (many thanks to Hans Passant):

private Image RotateImage(Image img, float rotationAngle)
    {
        Image image = new Bitmap(img.Width * 2, img.Height * 2);
        Graphics gfx = Graphics.FromImage(image);

        int center = (int)Math.Sqrt(img.Width * img.Width + img.Height * img.Height) / 2;
        gfx.TranslateTransform(center, center);
        gfx.RotateTransform(rotationAngle);
        gfx.DrawImage(img, -img.Width / 2, -img.Height / 2);

        return image;
    }

这是同样的事情作为他的，只是在每个图像的基础上，而不是一种形式。

It's the same thing as his, just on a per image basis, as opposed to a form.

推荐答案

您都挖自己更深的一个洞。这不顺心年初，旋转位图的大小是不宽x高。这也是非常低效的。你需要得到RotateTransform去，重要的是还可以使用TranslateTransform，并选择正确的图像绘制的位置。

You are digging yourself a deeper hole. This goes wrong early, the size of the rotated bitmap is not Width x Height. It is also very inefficient. You need to get RotateTransform going, it is important to also use TranslateTransform and pick the correct image drawing location.

下面是一个示例Windows窗体应用程序，绕其中心点位图，偏移就足以触摸形式的内缘，当它旋转。在表单上放一个计时器，并与项目+属性，资源选项卡中添加图像资源。将它命名为SampleImage，它不必是正方形。使code是这样的：

Here's a sample Windows Forms app that rotates a bitmap around its center point, offset just enough to touch the inner edge of the form when it rotates. Drop a Timer on the form and add an image resource with Project + Properties, Resource tab. Name it SampleImage, it doesn't have to be square. Make the code look like this:

public partial class Form1 : Form {
    private float mDegrees;
    private Image mBmp;
    public Form1() {
        InitializeComponent();
        mBmp = Properties.Resources.SampleImage;
        timer1.Enabled = true;
        timer1.Interval = 50;
        timer1.Tick += new System.EventHandler(this.timer1_Tick);
        this.DoubleBuffered = true;
    }
    private void timer1_Tick(object sender, EventArgs e) {
        mDegrees += 3.0F;
        this.Invalidate();
    }
    protected override void OnPaint(PaintEventArgs e) {
        int center = (int)Math.Sqrt(mBmp.Width * mBmp.Width + mBmp.Height * mBmp.Height) / 2;
        e.Graphics.TranslateTransform(center, center);
        e.Graphics.RotateTransform(mDegrees);
        e.Graphics.DrawImage(mBmp, -mBmp.Width/2, -mBmp.Height/2);
    }
}

您可以通过创建32bppPArgb格式的位图绘制速度快了很多，我跳过这一步。

You can make draw a lot faster by creating a bitmap in the 32bppPArgb format, I skipped that step.

这篇关于LockBits图像旋转方法不工作？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！