＆之间的差异放大器;和＆功放;＆安培; [英] Difference between & and &&

问题描述

我始终认为，＆放大器;＆功放;在Java 运算符用于验证是否其两个布尔操作数是真正和＆放大器; 运算符是用来做两个整数类型位运算

I always thought that && operator in Java is used for verifying whether both its boolean operands are true, and the & operator is used to do Bit-wise operations on two integer types.

最近，我才知道，＆安培; 运营商也可以用来验证其两个布尔操作数是否真正中，唯一的区别是它检查即使在LHS操作数是假的RHS操作数。

Recently I came to know that & operator can also be used verify whether both its boolean operands are true, the only difference is that it checks the RHS operand even if the LHS operand is false.

是＆功放;在Java 运算符重载的内部？或者是有这背后一些其他的概念？

Is the & operator in Java internally overloaded? Or is there some other concept behind this?

推荐答案

＆安培; ＆LT; - 验证两个操作数结果
＆功放;＆安培; ＆LT; - 如果第一个操作数计算结果为假，因为其结果将是错误的停止评估

& <-- verifies both operands
&& <-- stops evaluating if the first operand evaluates to false since the result will be false

＆安培; （1 / X＆GT; 1）＆LT; - 这意味着评估 然后评估（（X = 0！） 1 / X＆GT; 1）然后执行＆放;.的问题是，对于x = 0，这将抛出异常。

(x != 0) & (1/x > 1) <-- this means evaluate (x != 0) then evaluate (1/x > 1) then do the &. the problem is that for x=0 this will throw an exception.

＆放大器;＆安培; （1 / X＆GT; 1）＆LT; - 这意味着评估（！X = 0），只如果这是真的，那么评估（1 / X＆GT; 1）所以如果你有X = 0，那么这是完全安全的，不会抛出，如果任何异常的计算结果为假（X = 0！）整个事情的直接计算结果为假，而不评估（1 / X＆GT; 1）。

(x != 0) && (1/x > 1) <-- this means evaluate (x != 0) and only if this is true then evaluate (1/x > 1) so if you have x=0 then this is perfectly safe and won't throw any exception if (x != 0) evaluates to false the whole thing directly evaluates to false without evaluating the (1/x > 1).

编辑：

exprA | exprB ＆LT; - 这意味着评估 exprA 然后评估 exprB 然后执行 |

exprA | exprB <-- this means evaluate exprA then evaluate exprB then do the |.

exprA || exprB ＆LT; - 这意味着评估 exprA 键，只有当这是假然后评估 exprB 并执行 || 。

exprA || exprB <-- this means evaluate exprA and only if this is false then evaluate exprB and do the ||.

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