如果有很多或者在承包形式的Python [英] Python if with many or in a contracted form

问题描述

我正在学习Python和我发现自己失去了试图创建一个if语句应该是真，如果用户输入y或肯定。

I'm learning python and I found myself lost trying to create a an if statement that should be true if the user input y or yes.

#!/usr/bin/env python3

user_input = input('Would you like to go on?')
lowui = user_input.lower

if lowui == ('y' or 'yes'):
   print('You want to go on')
else
   print('See you later, bye')

问题是，它成为真正只有当我键入y但不是肯定的。如果删除了括号就变成始终为false。好吧，我可以不喜欢

The problem is that it becomes true only if I type y but not for yes. If I remove the parenthesis it becomes always false. Ok, I can do a workaround like

if lowui == 'y' or lowui == 'yes':

但我想知道是否有不逼我写了这么多次塔变量的任何伎俩。结果
谢谢你在前进。

but I was wondering if there is any trick that don't force me to write so many times tha variable.
Thank you in advance.

推荐答案

将其更改为

if lowui in ('y', 'yes'):

另外这是错误的：

Also this is wrong:

lowui = user_input.lower

应该是：

lowui = user_input.lower() # Actually call the lower function

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