Python的＆QUOT;和＆QUOT;运营商整数 [英] Python "and" operator with ints

问题描述

，这是什么行为在Python？

What is the explanation for this behavior in Python?

a = 10
b = 20
a and b # 20
b and a # 10

a和b 的计算结果为20，而 B和的计算结果为10相当于真阳性整数？为什么它评估为第二个值？因为是第二次？

a and b evaluates to 20, while b and a evaluates to 10. Are positive ints equivalent to True? Why does it evaluate to the second value? Because it is second?

推荐答案

解释了这个相当不错：

The documentation explains this quite well:

这位前pression x和y 首先评估 X ;如果 X 是假的，它的值返回;否则，是评估并返回结果值。

The expression x and y first evaluates x; if x is false, its value is returned; otherwise, y is evaluated and the resulting value is returned.

和同样为或这将可能是你的嘴唇上的下一个问题。

And similarly for or which will probably be the next question on your lips.

这位前pression x或y 首先评估 X ;如果 X 是真实的，它的值返回;否则，是评估并返回结果值。

The expression x or y first evaluates x; if x is true, its value is returned; otherwise, y is evaluated and the resulting value is returned.

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