比较两个字符串与布尔？ [英] Comparing two strings with boolean?

问题描述

我尝试这个code的写作练习，我这样就失去了！

I was trying this code writing exercise and I am so lost!

这次演习是：

完成这需要两个字符串和一个布尔值，输入方法。如果布尔是真实的，这种方法的第一个两个字符串比较，不考虑大小写（大写/小写）。两个字符串被认为是相等忽略大小写，如果他们是相同的长度，并在两个字符串对应的字符等于忽略大小写。

Complete the method which takes two Strings and one boolean as input. If the boolean is true, this method compares the first two Strings, ignoring case considerations (uppercase/lowercase). Two Strings are considered equal ignoring case if they are of the same length, and corresponding characters in the two Strings are equal ignoring case.

如果布尔是假的，这个方法应该比较两个字符串，返回true，如果第一个字符串再presents字符作为第二个字符串的相同序列，否则为false。

If the boolean is false, this method should compare two Strings and return true if the first String represents the same sequence of characters as the second String, otherwise false.

请注意： compareTwoStrings（HELLO，，FALSE）应该返回false

Note: compareTwoStrings("HELLO", "", false) should return false.

和这里是我的尝试：

public boolean compareTwoStrings (String a, String b, boolean isIgnoreCase) 
{ 
    if (a.equalsIgnoreCase(b)) {
        return (isIgnoreCase==true);
    }
    else if (a.equals(b)) {
       return (isIgnoreCase==false);
    }
}

它甚至不进行编译，但即使这样做，我敢肯定，这是行不通的。

It doesn't even compile, but even if it did, I'm sure it wouldn't work.

推荐答案

您正在向后做。主题说：如果布尔是真实的，那么这样做，否则的话做。所以，你应该以同样的方式编程的：

You're doing it backwards. The subject says: if the boolean is true, then do this, else, then do that. So you should program it the same way:

if (isIgnoreCase) {
    return ...
}
else {
    return ...
}

其余部分留作练习。您应该能够通过自己看着办吧。

The rest is left as an exercise. You should be able to figure it out by yourself.

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