使用boost ::蓄电池，我怎么能重置滚动窗口的大小，它保持额外的历史？ [英] Using boost::accumulators, how can I reset a rolling window size, does it keep extra history?

问题描述

我期待在了boost ::累加器框架，特别是一对夫妇的rolling_window计算。

I am looking at the boost::accumulator framework, specifically a couple of the rolling_window calculations.

#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/rolling_mean.hpp>
accumulator_set<int, stats<tag::rolling_mean> > acc(tag::rolling_window::window_size = 3);

正如你看到这里，我已经设置了WINDOW_SIZE是三，使得它保持了最后三个样本的平均值平均只有

As you see here, I have set the window_size to be three, such that it is maintaining the mean average of the last three samples only.

我可以修改的大小在运行时，也许是基于用户设置？

Can I amend that size at run-time, perhaps based on a user setting?

如果是这样，我增加了WINDOW_SIZE确实累加器有，如果它已经看到了比我的新WINDOW_SIZE更多额外的内部状态，否则我将不得不等待额外的价值？

If so, and I increase the window_size does the accumulator have extra internal state if it had already seen more than my new window_size, or would I have to wait for the extra values?

推荐答案

重置升压蓄电池的最佳方式是将其分配到一个新的。例如：

The best way to reset a boost accumulator is to assign it to a new one. For example:

typedef accumulator_set<int, ... template crazyness tags ... > window_acc;

window_acc acc;
acc(1);
acc(2);
...
// reset
acc = window_acc();

其实，交换会在这里pferred $ P $，但accumulator_set没有交换成员= \\

Actually, swap would be preferred here, but accumulator_set doesn't have a swap member =\

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