如何把成果转化为使用升压精神STL的地图吗? [英] How to put results into a STL map by using boost-spirit?
问题描述
#include <QtCore/QCoreApplication>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <iostream>
#include <string>
#include <list>
#include <map>
#define CODE_CPP_KEYWORD_ENUM "enum"
namespace haha
{
//简单表示c++的enum的类(A structure use to simply description C++ enum)
struct CPPCodeEnum
{
//enum的名称(enum Name)
::std::string enumName;
//成员的名称(enum Members‘name)
::std::list<::std::string> enumMembers;
};
}
namespace haha
{
namespace fusion = boost::fusion;
namespace phoenix = boost::phoenix;
namespace qi = boost::spirit::qi;
namespace ascii = boost::spirit::ascii;
//enum的简单解析器
template <typename Iterator>
struct CPPCodeEnumGrammar
: qi::grammar<Iterator, CPPCodeEnum(),ascii::space_type >
{
CPPCodeEnumGrammar()
: CPPCodeEnumGrammar::base_type(start)
{
using qi::_val;
using qi::_1;
using qi::lit;
using qi::lexeme;
using qi::raw;
using qi::space;
using ascii::char_;
using ascii::string;
using phoenix::push_back;
//解析一个变量名(他不符合C++的命名规范,暂时只是个替代品)
quoted_string = lexeme[+(qi::alpha|qi::digit | char_('_'))];
start =
//解析"enum"
lit(CODE_CPP_KEYWORD_ENUM)>>
//取得enum名
*quoted_string[ phoenix::bind(&CPPCodeEnum::enumName, _val)= _1]>>
char_("{")>>
//解析enum的成员
*(quoted_string[push_back(phoenix::bind(&CPPCodeEnum::enumMembers, _val), _1)]%',')>>
//可有可无的逗号小尾巴
-char_(",")>>
char_("}");
}
qi::rule<Iterator, std::string(),ascii::space_type > quoted_string;
qi::rule<Iterator, CPPCodeEnum(), ascii::space_type > start;
};
}
int main(int argc, char *argv[])
{
QCoreApplication a(argc, argv);
//模拟C++的一段代码(test string simulate a section of C++ code)
::std::string teststr="enum myename {m1,m2 ,m3 ,m4 ,}";
using boost::spirit::ascii::space;
std::string::const_iterator iter = teststr.begin();
std::string::const_iterator end = teststr.end();
haha::CPPCodeEnumGrammar<std::string::const_iterator> myCPPCodeEnumGrammar;
haha::CPPCodeEnum data;
bool r = phrase_parse(iter, end, myCPPCodeEnumGrammar, space, data);
return a.exec();
}
以上我的code正常工作,但是,它是太简单,不解析code是这样的:(枚举myename {M1 = 1,M2 = 44立方米= 89,M4 = 0,} )。我需要同时枚举members'name和value.Now我决定另一种类型的CPP codeEnum :: enumMembers
My code above works correctly,however,it is too simple and not to parse code like this:(enum myename {m1=1,m2=44 ,m3=89 ,m4=0 ,}).I need both enum members’name and value.Now I decide alternative type of "CPPCodeEnum::enumMembers"
list < std::string::string>
与
map < std::string::string,int>
。但我不知道如何把成果转化为一个STL的地图使用升压精神?
.But I do not know how to put results into a STL map by using boost-spirit?
推荐答案
请看看<一个href=\"http://boost-spirit.com/home/articles/qi-example/parsing-a-list-of-key-value-pairs-using-spirit-qi/\"相对=nofollow>这篇文章,这说明正是你想要达到的目标。该要点是,Spirit.Qi允许直接解析键/值对成图没有任何额外的code。
Please have a look at this article, which describes exactly what you're trying to achieve. The gist is that Spirit.Qi allows to directly parse the key/value pairs into a map without any additional code.
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