的boost ::标记生成逗号分隔（C ++） [英] Boost::tokenizer comma separated (c++)

问题描述

应该是你们一个容易.....

Should be an easy one for you guys.....

我和断词使用Boost玩弄，我想创建一个逗号分隔的令牌。这里是我的code：

I'm playing around with tokenizers using Boost and I want create a token that is comma separated. here is my code:

    string s = "this is, , ,  a test";
boost::char_delimiters_separator<char> sep(",");
boost::tokenizer<boost::char_delimiters_separator<char>>tok(s, sep);


for(boost::tokenizer<>::iterator beg= tok.begin(); beg!=tok.end(); ++beg)
{
    cout << *beg << "\n";
}

这是我想要的输出是：

This is


 a test

我所得到的是：

This
is
,
,
,
a
test

更新时间：

推荐答案

您必须给分隔标记生成器！

You must give the separator to tokenizer!

boost::tokenizer<boost::char_delimiters_separator<char>>tok(s, sep);

此外，更换德precated char_delimiters_separator与char_delimiter：

Also, replace the deprecated char_delimiters_separator with char_delimiter:

string s = "this is, , ,  a test";
boost::char_separator<char> sep(",");
boost::tokenizer< boost::char_separator<char> > tok(s, sep);
for(boost::tokenizer< boost::char_separator<char> >::iterator beg = tok.begin(); beg != tok.end(); ++beg)
{
    cout << *beg << "\n";
}

请注意，也有一个模板参数不匹配：这是很好的习惯，这样的typedef复杂类型：所以最终的版本可能是：

Please note that there is also a template parameter mismatch: it's good habit to typedef such complex types: so the final version could be:

string s = "this is, , ,  a test";
boost::char_separator<char> sep(",");
typedef boost::tokenizer< boost::char_separator<char> > t_tokenizer;
t_tokenizer tok(s, sep);
for (t_tokenizer::iterator beg = tok.begin(); beg != tok.end(); ++beg)
{
    cout << *beg << "\n";
}

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