创建通过反射委托 [英] Create delegate via reflection

问题描述

由于包含程序集

namespace Foo{public class Bar;}

我怎么能创建一个动作＆LT; Foo.Bar＆GT; 从没有在编译时引用的第一个组件的另一个组件

How could I create an Action<Foo.Bar> from another assembly without referencing the first assembly at compile time?

推荐答案

如果您使用

Type barType = Type.GetType("Foo.Bar, whateverassembly");
Type actionType = typeof(Action<>).MakeGenericType(barType);

操作类型现在将重新present 动作＆LT; Foo.Bar＆GT; 。但是，要使用它，你需要contintue使用反射，所以你需要找到一个的MethodInfo 适合签名无效（ Foo.Bar）和呼叫 Delegate.CreateDelegate 来创建一个委托。你还需要 Delegate.DynamicInvoke 来执行它。

actionType will now represent Action<Foo.Bar>. However, to use it, you'll need to contintue to use reflection, so you'll need to find a MethodInfo that fits the signature void(Foo.Bar), and call Delegate.CreateDelegate to create a delegate. And you'll need Delegate.DynamicInvoke to execute it.

Delegate call = Delegate.CreateDelegate(actionType, ...);
...
call.DynamicInvoke(someBar);

有个声音告诉我，不是你想的是什么...

Something tells me that's not what you're thinking of...

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