Android的广播接收器android.intent.action.BATTERY_CHANGED [英] Android BroadcastReceiver android.intent.action.BATTERY_CHANGED
问题描述
我能够监听意图 Intent.ACTION_BATTERY_CHANGED
我的活动范围内,它的伟大工程。我试图在清单中定义接收器:
I am able to listen for the Intent Intent.ACTION_BATTERY_CHANGED
within my activity and it works great. I tried defining the receiver in the manifest:
<receiver android:name="com.beargreaves.battery.BatteryReceiver">
<intent-filter>
<action android:name="android.intent.action.BATTERY_CHANGED" />
</intent-filter>
</receiver>
但它没有工作,我读了在这里说,它必须以编程定义一个职位。而不是在我的活动接收器注册,我想在一个服务实现这一目标,使其持续监控。我已经成功地实现了这一点,它的工作原理,但我想检查我的工作,看它是否是正确的做法。
but it didn't work, I read a post on here saying that it must be defined programmatically. Rather than registering for the receiver in my Activity, I wanted to achieve this in a Service so that it continually monitors. I have successfully achieved this, and it works, but I wanted to check my working to see if it is the correct approach.
我开始通过延长广播接收器:
I started by extending BroadcastReceiver:
public class BatteryReceiver extends BroadcastReceiver{
@Override
public void onReceive(Context context, Intent intent) {
Bundle bundle = intent.getExtras();
if(null == bundle)
return;
boolean isPresent = intent.getBooleanExtra("present", false);
String technology = intent.getStringExtra("technology");
int plugged = intent.getIntExtra("plugged", -1);
int scale = intent.getIntExtra("scale", -1);
int health = intent.getIntExtra("health", 0);
int status = intent.getIntExtra("status", 0);
int rawlevel = intent.getIntExtra("level", -1);
int level = 0;
Log.d("Debug","Battery Receiver OnReceive");
if(isPresent) {
if (rawlevel >= 0 && scale > 0) {
level = (rawlevel * 100) / scale;
Log.d("Debug","BatterReceiver: " + level);
Toast.makeText(context,"Battery Receiver: " + level + "\t" + status + "Raw: " + rawlevel,Toast.LENGTH_LONG).show();
if(level <60) {
/*
* Only invoke the service when level below threshold
*/
Intent i = new Intent(context, BatteryService.class);
i.putExtra("level", level);
context.startService(i);
}
}
}
}
}
然后我用一个服务首先注册在的onCreate()
接收器,然后处理在onStart事件()
。我的广播接收器开始服务,如果电平低于一个阈值
And then I use a Service to first register the receiver in onCreate()
and then handle the events in onStart()
. My BroadcastReceiver starts the Service if the level is below a threshold.
public class BatteryService extends Service {
/*
* First Call to onStart we don't want to do anything
*/
boolean avoidFirst = false;
private BroadcastReceiver receiver;
@Override
public IBinder onBind(Intent intent) {
// TODO Auto-generated method stub
return null;
}
@Override
public void onCreate() {
super.onCreate();
IntentFilter filter = new IntentFilter(Intent.ACTION_BATTERY_CHANGED);
receiver = new BatteryReceiver();
registerReceiver(receiver, filter);
}
@Override
public void onStart(Intent intent, int startId) {
Log.d("Debug","Battery Service On Start");
int level = intent.getIntExtra("level", -1);
if(avoidFirst) {
if(level != -1) {
Log.d("Debug","Battery Alert Notifying..... " + level);
SMSManager.sendSMS(BatteryService.this, "<number redacted>", "Battery Level Aleart: " + level);
stopSelf();
}
} else {
avoidFirst = true;
}
}
@Override
public void onDestroy() {
// TODO Auto-generated method stub
super.onDestroy();
PreferenceUtil.updatePreference(BatteryService.this, "battery_monitor_on", false);
unregisterReceiver(receiver);
}
}
这是正确的做法?是寄存器的onCreate()
接收器,然后当接收到事件启动该服务。首先,我试图不使用服务,但后来我都没有注册接收器,因为它可以在清单中不是可以实现的方式。其次,当我试图在发送短信时抛出异常的onReceive()
。我读的onReceive()
不应该开始任何线程。
Is this the correct approach? Be that register the receiver in onCreate()
and then start the Service when an event is received. First I tried not using a Service but then I have no way of registering the receiver since it can't be achieved in the manifest. Secondly an exception was thrown when I tried to send a text message in the onReceive()
. I read that onReceive()
shouldn't be starting any threads.
在此先感谢
推荐答案
是的,这看起来像一个非常不错的办法。这是相当类似的(实际上有所好转,我会说)比我有我的应用程序,(已多年运作良好)做的。
Yes, that looks like a very good approach. It's quite similar (actually somewhat better, I'd say) than what I do with my app, (which has been working well for years).
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