如何通过长时间pressGestureRecognizer得到button.tag? [英] How to get button.tag via longPressGestureRecognizer?
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问题描述
我动态地添加图像按钮一些滚动视图。他们都指向一个长pressHandler。现在,我怎么哪个按钮被pressed?在[发件人标签]给我,我加入按钮longGestureRecognizer的标签,我不能手动设置标签。
的(...){
* UIButton的按钮= [[UIButton的页头]初始化];
button.tag = W + H * 3;
[按钮addTarget:自我行动:@selector(ImageButton的pressed :) forControlEvents:UIControlEventTouchUpInside];
UILong pressGestureRecognizer *武功= [[UILong pressGestureRecognizer页头]
initWithTarget:自我行动:@selector(imageButtonLong preSS :)]。
gest.minimum pressDuration = 1;
gest.delegate =自我; [按钮addGestureRecognizer:武功];
[武功发布] [滚动视图addSubview:键];
[按钮释放];
} - (无效)imageButtonLong preSS:(ID)发送{
//如何在这里得到按钮的标签?
}
解决方案
有一个视图
在 UIGestureRecognizer财产
它返回识别器被附接到图。我认为这是你最好的选择。
- (无效)imageButtonLong preSS:(ID)发送{
UIGestureRecognizer *识别=(UIGestureRecognizer *)寄件人;
INT标记= recognizer.view.tag;
}
I'm dynamically adding image buttons to some scrollview. They all point at one longPressHandler. Now, how do I get which button was pressed? The [sender tag] gives me the tag of longGestureRecognizer that I added to button and I can't manually set that tag.
for (...) {
UIButton *button = [[UIButton alloc] init];
button.tag = w + h * 3;
[button addTarget:self action:@selector(imageButtonPressed:) forControlEvents:UIControlEventTouchUpInside];
UILongPressGestureRecognizer *gest = [[UILongPressGestureRecognizer alloc]
initWithTarget:self action:@selector(imageButtonLongPress:)];
gest.minimumPressDuration = 1;
gest.delegate = self;
[button addGestureRecognizer:gest];
[gest release];
[scrollView addSubview:button];
[button release];
}
- (void) imageButtonLongPress:(id)sender {
// how to get button tag here?
}
解决方案
There is a view
property in the UIGestureRecognizer
which returns the view that recognizer is attached to. I think that is your best bet.
- (void) imageButtonLongPress:(id)sender {
UIGestureRecognizer *recognizer = (UIGestureRecognizer*) sender;
int tag = recognizer.view.tag;
}
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