从一个函数返回多个值 [英] returning multiple values from a function

问题描述

谁能告诉我如何从一个函数返回多个值？结果
请用一些例子解释一下？

Can anyone tell me how to return multiple values from a function?
Please elaborate with some example?

推荐答案

在这里你的选择是要么返回一个结构与你喜欢的元素，或者用做指针处理参数的函数。

Your choices here are to either return a struct with elements of your liking, or make the function to handle the arguments with pointers.

/* method 1 */
struct Bar{
    int x;
    int y;
};

struct Bar funct();
struct Bar funct(){
    struct Bar result;
    result.x = 1;
    result.y = 2;
    return result;
}

/* method 2 */
void funct2(int *x, int *y);
void funct2(int *x, int *y){
    /* dereferencing and setting */
    *x  = 1;
    *y  = 2;
}

int main(int argc, char* argv[]) {
    struct Bar dunno = funct();
    int x,y;
    funct2(&x, &y);

    // dunno.x == x
    // dunno.y == y
    return 0;
}

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