获得在C文件中的内容，最简单的方法 [英] Easiest way to get file's contents in C

问题描述

什么是最简单的方法（最不容易出错，code的最小行，但是你要跨preT吧）开在C文件并阅读其内容为一个字符串（字符*，的char []，等等）？

What is the simplest way (least error-prone, least lines of code, however you want to interpret it) to open a file in C and read its contents into a string (char*, char[], whatever)?

推荐答案

我倾向于只加载整个缓冲区作为原料内存块到内存中，并做我自己的解析。这样，我有比标准库确实在多个平台上最擅长的控制。

I tend to just load the entire buffer as a raw memory chunk into memory and do the parsing on my own. That way I have best control over what the standard lib does on multiple platforms.

这是一个存根我用这个。您可能还需要检查错误 - codeS fseek的，FTELL和FREAD。 （省略清晰）。

This is a stub I use for this. you may also want to check the error-codes for fseek, ftell and fread. (omitted for clarity).

char * buffer = 0;
long length;
FILE * f = fopen (filename, "rb");

if (f)
{
  fseek (f, 0, SEEK_END);
  length = ftell (f);
  fseek (f, 0, SEEK_SET);
  buffer = malloc (length);
  if (buffer)
  {
    fread (buffer, 1, length, f);
  }
  fclose (f);
}

if (buffer)
{
  // start to process your data / extract strings here...
}

这篇关于获得在C文件中的内容，最简单的方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！