是否有产生三角波一行功能？ [英] Is there a one-line function that generates a triangle wave?

问题描述

在类似的方式模的生成锯齿波。它不必是连续的。

这里是我的意思是：

  INT M = 10;
INT X = 0;
INT I = 0;
而（ⅰ＆下; M * 3）{
    的printf（％D，X）;
    X ++;
    X = X％米;
    我++;
}
 

生成一个序列0..9，三次看起来像这样：

的注意，峰右侧的斜率仅仅是一个图形神器的

一班轮在这种情况下的 X = 1 +％M

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我想是这样的：

如果你知道单行为其他波形（正弦波，方波），这将是很好的了解为好。

更新：每个人的答案都非常有帮助，我有一个跟进的问题。

什么会被添加到三角波函数以使线曲线的斜率或缩小这样的：

谢谢大家，你不同的答案让我从一个更大的视角看问题。特别感谢诺多为他取的公式延伸到二次曲线。

解决方案

  X =米 -  ABS（I％（2 * M） -  M）
 

In a similar way that modulo generates a sawtooth wave. It doesn't have to be continuous.

here is what i mean:

int m = 10;
int x = 0;
int i = 0;
while (i < m*3) {
    printf("%d ", x);
    x++;
    x = x % m;
    i++;
}

generates a sequence 0..9, three times which looks like this:

note that the slope on the right side of the peak is just a graphing artifact

The one-liner in this case is x = i++ % m

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What I want is this:

If you know one-liners for the other wave forms (sine, square), that would be good to know as well.

Update: everyone's answers have been very helpful and I have a follow-up question.

What would be added to the triangle wave function to make the slope of the lines curve in or out like this:

Thanks everyone, your varied answers helped me see the problem from a larger perspective. Special thanks to Noldorin for his take on extending the equation to quadratic curves.

解决方案

x = m - abs(i % (2*m) - m)

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