C / C ++程序，它打印自己的源$ C ​​$ C作为其输出 [英] C/C++ program that prints its own source code as its output

问题描述

维基百科说，它之所以被称为奎因，有人给了code如下：

Wikipedia says it's called a quine and someone gave the code below:

char*s="char*s=%c%s%c;main(){printf(s,34,s,34);}";main(){printf(s,34,s,34);}

但是，很明显你要添加

But, obviously you have to add

#include <stdio.h> //corrected from #include <stdlib.h>

，使的printf（）可以工作。

从字面上看，因为上面的程序没有打印的#include＆LT;＆stdio.h中GT;（？），这是没办法了。

Literally, since the above program did not print #include <stdio.h>, it is not a solution (?)

我感到困惑的打印其自己的源$ C ​​$ C，而这种问题的任何目的，字面要求尤其是在面试。

I am confused about the literal requirement of "print its own source code", and any purpose of this kind of problems, especially at interviews.

推荐答案

这里的窍门是，大多数编译器编译，而不需要包括 stdio.h中。

The trick here is that most compilers will compile without requiring you to include stdio.h.

他们通常只是抛出一个警告。

They will usually just throw a warning.

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