为什么编译器还允许初始化的变量与自身？ [英] Why does the compiler allow initializing a variable with itself?

问题描述

我终于追查下来一个错字的错误，这是类似以下code的东西。
但不应编译器检测到这个（默认选项）？

 的#include＆LT;＆stdio.h中GT;诠释的main（）
{
    INT C = C;
    返回的printf（％d个\\ N，C）;
}
$ GCC --version
海湾合作委员会（Ubuntu的4.4.3-4ubuntu5.1）4.4.3
 

解决方案

我不明白为什么它不会编译。定义发生初始化之前。当然，这个初始化是没有意义的，但是，没有理由它不会从编译器工作的站立点。

C不具有相同类型的保护，像C＃更现代的语言都具有的。 C＃编译器会给您使用一个未分配的变量错误。 C不关心。它不会保护你自己。

I finally trace down a typo bug, which is something similar to the following code. But shouldn't the compiler detect this (by default options)?

#include <stdio.h>

int main()
{
    int c = c;
    return printf("%d\n", c);
}


$ gcc --version        
gcc (Ubuntu 4.4.3-4ubuntu5.1) 4.4.3

解决方案

I don't see why it wouldn't compile. Definition happens prior to initialization. Of course this initialization is pointless, however, there's no reason it wouldn't work from the compilers stand point.

C does not have the same types of protections that more modern languages like C# have. The C# compiler would give an error that you're using an unassigned variable. C doesn't care. It will not protect you from yourself.

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