为什么我不能用这个code覆盖一个字符串? [英] Why can't I use this code to overwrite a string?
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问题描述
code
#include "stdio.h"
#include "string.h"
int main()
{
char *p = "abc";
printf("p is %s \n", p);
return 0;
}
输出
p is abc
code
#include "stdio.h"
#include "string.h"
int main()
{
char *p = "abc";
strcpy(p, "def");
printf("p is %s \n",p);
return 0;
}
输出
Segmentation fault (core dumped)
有人能解释为什么出现这种情况?
Could someone explain why this happens?
推荐答案
在您的code:
char *p="abc";
p指向字符串文本 - 你不能改变字符串文字,这是你对strcpy的呼叫尝试做的。相反,使P上数组:
p points to a string literal - you are not allowed to change string literals, which is what your call to strcpy is trying to do. Instead, make p an array:
char p[] = "abc";
这将文字复制到的东西,你被允许修改。
which will copy the literal into something that you are allowed to modify.
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