使用整数scanf函数分段故障 [英] segmentation fault using scanf with integer

问题描述

我在我的C code试图读取用户与以下functon整数输入时得到一个分段错误：

  INT userChoice = 0，TS;
浮TR，TW，TP，AP;
炭标题[35]，TITLE2 [35];
书* CURR;
而（userChoice！= 9）{
    的printf（1确定并打印总收入\\ n）;
    的printf（2确定并打印总成本批发\\ n）;
    的printf（3确定并打印利润总额\\ n）;
    的printf（4确定并打印销售的\\ n总数。）;
    输出（5确定并打印每销售\\ n平均利润。）;
    的printf（6打印簿列表\\ n）;
    的printf（7添加书\\ n）;
    的printf（8删除书\\ n）;
    的printf（9退出程序\\ n）;
    scanf函数（％D，userChoice）;
    ...
    ...
 

我执行我的程序时，它都会让我进入分配给userChoice的数量，但经过赛格故障立即生效。任何帮助吗？谢谢！

编辑：确切的错误我收到我：

 程序接收到的信号SIGSEFV，Segmentaion故障。
从/lib64/libc.so.6 0x0000003503256f50在_IO_vfscanf_i​​nternal（）
 

解决方案

应该是：

  scanf函数（％d个，＆安培; userChoice）;
 

极品符号读取到userChoice的位置，而不是userChoice的价值。

I am getting a segmentation fault in my C code when trying to read integer input from the user with the following functon:

int userChoice = 0, tS;
float tR, tW, tP, aP;
char title[35], title2[35];
Book *curr;
while (userChoice != 9) {
    printf("1. Determine and print total revenue\n");
    printf("2. Determine and print total wholesale cost\n");
    printf("3. Determine and print total profit\n");
    printf("4. Determine and print total number of sales\n");
    printf("5. Determine and print average profit per sale\n");
    printf("6. Print book list\n");
    printf("7. Add book\n");
    printf("8. Delete book\n");
    printf("9. Exit the program\n");
    scanf("%d", userChoice);
    ...
    ...

Every time I execute my program, it allows me to enter the number to be assigned to userChoice, but seg faults immediately after. Any help? Thanks!

Edit: The exact error I'm getting i:

Program received signal SIGSEFV, Segmentaion fault. 
0x0000003503256f50 in _IO_vfscanf_internal () from /lib64/libc.so.6

解决方案

Should be:

scanf("%d", &userChoice);

Need the ampersand to read it into the location of userChoice, and not the value of userChoice.

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