阅读C ++字符串scanf函数 [英] Read C++ string with scanf

问题描述

正如标题所说，我很好奇，如果有读取一个C ++字符串scanf函数的方式。

As the title said, I'm curious if there is a way to read a C++ string with scanf.

我知道我可以阅读每个字符和应有的字符串插入，但我想是这样的：

I know that I can read each char and insert it in the deserved string, but I'd want something like:

string a;
scanf("%SOMETHING", &a);

获得（）也不起作用。

在此先感谢！

推荐答案

有没有的情况下获得（）是要使用！它的总是错误使用获得（），它是由C11删除，并且从C ++ 14被删除。

There is no situation under which gets() is to be used! It is always wrong to use gets() and it is removed from C11 and being removed from C++14.

scanf（）的好好尝试一下支持任何C ++类。但是，您可以scanf（）的存储从结果成的std ::字符串：

scanf() doens't support any C++ classes. However, you can store the result from scanf() into a std::string:

std::string str(100, ' ');
if (1 == scanf("%*s", &str[0], str.size())) {
    // ...
}

我不能完全肯定指定在缓冲区lenght scanf函数的方式（）及顺序的参数去（有机会的参数＆放大器;海峡[0] 和 str.size（）需要予以转回，我可能会丢失一个。格式字符串）。请注意，生成的std ::字符串将包含终止空字符，它不会改变它的大小。

I'm not entirely sure about the way to specify that buffer lenght in scanf() and in which order the parameters go (there is a chance that the parameters &str[0] and str.size() need to be reversed and I may be missing a . in the format string). Note that the resulting std::string will contain a terminating null character and it won't have changed its size.

当然，我只想用如果（给std :: cin＆GT;＆GT; STR）{...} 但是这是一个不同的问题。

Of course, I would just use if (std::cin >> str) { ... } but that's a different question.

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