为什么C程序的打印0D而不是0? (EOF时发送,按Ctrl + D) [英] Why does C program print 0D instead of 0? (When EOF sent as Ctrl+D)
问题描述
OSX 10.6.8,GCC 4.2 86_64
OSX 10.6.8, GCC 4.2 86_64
#include <stdio.h>
/* count lines in input */
main()
{
int c, nl;
nl = 0;
while ((c = getchar()) != EOF)
if (c == '\n')
++nl;
printf("%d\n", nl);
}
运行
./a.out
preSS CTRL + D
发送EOF
0D
这应该只是0.为什么会追加D'这是什么意思?
It should be just 0. Why does it append D? What does it mean?
推荐答案
我已经看到了这一个 - 它搞糊涂了,太
I've seen this one - it confused me, too.
该终端呼应 ^ D
,然后 0
从程序的输出,覆盖插入符。
The terminal is echoing ^D
and then the 0
is output from the program, overwriting the caret.
您可以通过改变程序中的打印格式,以证明这一点\\ n%d个\\ N
。
You can demonstrate this by changing the print format in your program to "\n%d\n"
.
在问'为什么?',我去探索。答案是在tty设置。对于我的终端,从的stty -a
的输出是:
When asked 'Why?', I went exploring. The answer is in the tty settings. For my terminal, the output from stty -a
is:
speed 9600 baud; 65 rows; 120 columns;
lflags: icanon isig iexten echo echoe -echok echoke -echonl echoctl
-echoprt -altwerase -noflsh -tostop -flusho pendin -nokerninfo
-extproc
iflags: -istrip icrnl -inlcr -igncr ixon -ixoff ixany imaxbel iutf8
-ignbrk brkint -inpck -ignpar -parmrk
oflags: opost onlcr -oxtabs -onocr -onlret
cflags: cread cs8 -parenb -parodd hupcl -clocal -cstopb -crtscts -dsrflow
-dtrflow -mdmbuf
cchars: discard = ^O; dsusp = ^Y; eof = ^D; eol = <undef>;
eol2 = <undef>; erase = ^?; intr = ^C; kill = ^X; lnext = ^V;
min = 1; quit = ^\; reprint = ^R; start = ^Q; status = ^T;
stop = ^S; susp = ^Z; time = 0; werase = ^W;
注意 ECHOCTL
在第二行的末尾 - 它是回声控制字符
Notice the echoctl
at the end of the second line - it is for 'echo control characters'.
$ stty -echoctl
$ cat > /dev/null
asdsadasd
$ stty echoctl
$ cat > /dev/null
asasada^D
$
您无法看到它,但每个猫
命令,我输入一个控制-D 骨节病>在该行的末尾 ASD
字符,并创下返回后的第二个。提示在第二个例子删除第二呼应 ^ D
。
You can't see it, but for each cat
command, I typed a Control-D at the end of the line of asd
characters, and a second one after hitting return. The prompt erased the second echoed ^D
in the second example.
所以,如果你不喜欢控制字符被回荡,关掉呼应:
So, if you don't like the control characters being echoed, turn the echoing off:
stty -echoctl
外壳还可以得到的方式;我尝试用<大骨节病>控制-R 骨节病>和我的壳(庆典
)决定进入
(reverse-i-search)`': aasadasdadadasdadadadadadsad
我已经输入的ASD字符喧宾夺主序列,然后键入<大骨节病>控制-R 骨节病>,而这正是我在shell结束了。我打断;我不知道一个反向我搜索是什么,但我怀疑它是Emacs的杂交;这是不是我的预期。
I'd typed the unoriginal sequence of 'asd' characters and then typed Control-R, and this is where I ended up in the shell. I interrupted; I'm not sure what a reverse-i-search is, but I suspect it is Emacs-ish; it was not what I expected.
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